The position vector of a particle \(\overrightarrow r\) as a function of time \(t\) (in seconds) is \(\overrightarrow r=3 t \hat{i}+2t^2\hat j~\text{m}\). The initial acceleration of the particle is:
1. \(2~\text{m/s}^2\)
2. \(3~\text{m/s}^2\)
3. \(4~\text{m/s}^2\)

4. zero

Subtopic:  Acceleration |
 88%
From NCERT
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Coordinates of a particle as a function of time \(t\) are \(x= 2t\),
\(y =4t\). It can be inferred that the path of the particle will be:

1. Straight line

2. Ellipse

3. Parabola

4. Hyperbola
Subtopic:  Position & Displacement |
 76%
From NCERT
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At an instant, the velocity and acceleration of a particle moving in the XY plane are 2i^ + 3j^ m/s and -3i^+2j^ m/s2. Rate of change of speed of the particle at this instant is:

(1) 13 m/s2

(2) -1 m/s2

(3) 1 m/s2

(4) Zero

Subtopic:  Acceleration |
From NCERT
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A body started moving with an initial velocity of \(4\) m/s along the east and an acceleration \(1\) m/s2 along the north. The velocity of the body just after \(4\) s will be?

1. \(8\) m/s along East.
2. \(4 \sqrt{2} \) m/s along North-East.
3. \(8\) m/s along North.
4. \(4 \sqrt{2} \) m/s along South-East.
Subtopic:  Uniformly Accelerated Motion |
 78%
From NCERT
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The position vector of a particle is \(\vec{r}= a \sin\omega t \hat{i} + a\cos \omega t \hat{j}\). The velocity of the particle is:
1.  parallel to the position vector.
2.  at \(60^{\circ}\) with position vector.
3.  parallel to the acceleration vector.
4.  perpendicular to the position vector.
Subtopic:  Circular Motion |
 80%
From NCERT
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A projectile thrown from the ground has horizontal range R. If velocity at the highest point is doubled somehow, the new range will be:

(1) 3 R

(2) 1.5 R

(3) 3 R

(4) 2 R

Subtopic:  Projectile Motion |
From NCERT
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A particle is projected from the origin with velocity 4i^ + 9j^ m/s. The acceleration in the region is constant and -10j^ m/s2. The magnitude of velocity after one second is

(1) 8 m/s

(2) 15 m/s

(3) 17 m/s

(4) 27 m/s

Subtopic:  Projectile Motion |
 83%
From NCERT
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A particle is moving on a circular path of radius \(R.\) When the particle moves from point \(A\) to \(B\) (angle \( \theta\)), the ratio of the distance to that of the magnitude of the displacement will be:

         
1. \(\dfrac{\theta}{\sin\frac{\theta}{2}}\)
2. \(\dfrac{\theta}{2\sin\frac{\theta}{2}}\)
3. \(\dfrac{\theta}{2\cos\frac{\theta}{2}}\)
4. \(\dfrac{\theta}{\cos\frac{\theta}{2}}\)

Subtopic:  Position & Displacement |
 75%
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The horizontal range of a particle thrown from the ground is four times the maximum height. The angle of projection with the vertical is:

(1) 60°

(2) 30°

(3) 45°

(4) 90°

Subtopic:  Projectile Motion |
 88%
From NCERT
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A particle is thrown with a velocity of 40 m/s. If it passes A and B as shown in the figure at time t1 = 1 s and t2 = 3 s. The value of h is:

                              

(1) 15 m

(2) 10 m

(3) 30 m

(4) 20 m

Subtopic:  Projectile Motion |
 59%
From NCERT
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