| 1. | The acidic strength of HX (X=F, Cl, Br and I) follows the order: HF > HCI > HBr >HI |
| 2. | Fluorine exhibits - 1 oxidation state whereas other halogens exhibit +1, +3, +5 and +7 oxidation states also. |
| 3. | The enthalpy of dissociation of F2 is smaller than that of Cl2. |
| 4. | Fluorine is stronger oxidising agent than chlorine. |
| 1. | Se | 2. | Te |
| 3. | Po | 4. | O |
| 1. | Ga | 2. | In |
| 3. | Al | 4. | B |
Match the allotropes of cabon given in List I with the respective characteristics given in List II.
| List-I | List-II | ||
| A. | Coke | I. | Carbon atoms are sp3 hybridised. |
| B. | Diamond | II. | Used as a dry lubricant |
| C. | Fullerene | III. | Used as a reducing agent |
| D. | Graphite | IV. | Cage like molecules |
| Options: | (A) | (B) | (C) | (D) |
| 1. | III | IV | I | II |
| 2. | II | IV | I | III |
| 3. | IV | I | II | III |
| 4. | III | I | IV | II |
| 1. | Quartz is extensively used as a piezoelectric material. |
| 2. | Silicones are a group of organosilicon polymers, which have (-R2SiO-) as a repeating unit. |
| 3. | Basic structural unit in silicates is the SiO44– tetrahedron. |
| 4. | Feldspars are not aluminosilicates. |
| 1. | \(\mathrm{CH_3SiCl_3}\) | 2. | \(\mathrm{SiCl_4}\) |
| 3. | \(\mathrm{(CH_3)_2SiCl_2}\) | 4. | \(\mathrm{(CH_3)_3SiCl}\) |
| Assertion (A): | ICl is more reactive than I₂. |
| Reason (R): | I-Cl bond is weaker than I-I bond. |
| 1. | (A) is False but (R) is True. |
| 2. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 3. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 4. | (A) is True but (R) is False. |
| Statement I: | Acid strength increases in the order given as HF < HCl < HBr < HI. |
| Statement II: | As the size of the elements F, Cl, Br, I increases down the group, the bond strength of HF, HCI, HBr, and HI decreases and so the acid strength increases. |
| 1. | Statement I is correct and Statement II is incorrect |
| 2. | Statement I is incorrect and Statement II is correct. |
| 3. | Both Statement I and Statement II are correct. |
| 4. | Both Statement I and Statement II are incorrect. |
The incorrect statement regarding diamond and graphite is-
| 1. | In diamond each carbon is sp2 hybridised and in graphite, each carbon is sp3 hybridised. |
| 2. | Diamond is an insulator |
| 3. | Graphite has a planar geometry. |
| 4. | Both (2) and (3) |
Oxygen forms hydrogen bonds while chlorine does not, because :
| 1. | Chlorine has a bigger size and as a result, a higher electron density per unit volume. |
| 2. | Oxygen has a smaller size and as a result, a lower electron density per unit volume. |
| 3. | Oxygen has a smaller size and as a result, a higher electron density per unit volume. |
| 4. | Oxygen has a bigger size and as a result, a higher electron density per unit volume. |