Select Question Set:
Q. No.The chain length of silicones can be controlled by adding:
| 1. | \(\mathrm{CH_3SiCl_3}\) | 2. | \(\mathrm{SiCl_4}\) |
| 3. | \(\mathrm{(CH_3)_2SiCl_2}\) | 4. | \(\mathrm{(CH_3)_3SiCl}\) |
Subtopic: Properties of Structure of SiO2 & Other Compounds |
67%
Level 2: 60%+
NEET - 2022
Hints
Identify the correct statements among the following:
| a. | CO2 (g) is used as a refrigerant for ice-cream and frozen food. |
| b. | The structure of C60 contains twelve six-carbon rings and twenty five-carbon rings. |
| c. | ZSM-5, a type of zeolite, is used to convert alcohol into gasoline. |
| d. | CO is a colourless and odourless gas |
1. (a) and (c) only
2. (b) and (c) only
3. (c) and (d) only
4. (a), (b) and (c) only
Subtopic: Carbon Family - Preparations, Properties & Uses | Compounds of Carbon, Preparations, Properties & Uses |
71%
Level 2: 60%+
NEET - 2020
Hints
Subtopic: Introduction to Redox and Oxidation Number |
76%
Level 2: 60%+
NEET - 2019
Hints
Which one of the following orders is correct for the bond dissociation enthalpy of halogen molecules?
1. Cl2 > Br2 > F2 > l2
1. Cl2 > Br2 > F2 > l2
2. Br2 > l2 > F2 > Cl2
3. F2 > Cl2 > Br2 > l2
4. l2 > Br2 > Cl2 > F2
Subtopic: Group 17 - Preparation, Properties & Uses |
73%
Level 2: 60%+
NEET - 2016
Hints
Match the allotropes of cabon given in List I with the respective characteristics given in List II.
| List-I | List-II | ||
| A. | Coke | I. | Carbon atoms are sp3 hybridised. |
| B. | Diamond | II. | Used as a dry lubricant |
| C. | Fullerene | III. | Used as a reducing agent |
| D. | Graphite | IV. | Cage like molecules |
Choose the correct answer from the options given below:
| Options: | (A) | (B) | (C) | (D) |
| 1. | III | IV | I | II |
| 2. | II | IV | I | III |
| 3. | IV | I | II | III |
| 4. | III | I | IV | II |
Subtopic: Compounds of Carbon, Preparations, Properties & Uses |
76%
Level 2: 60%+
NEET - 2023
Hints
Select the correct option based on statements below:
| Assertion (A): | Both rhombic and monoclinic sulphur exist as S8 but oxygen exists as O2. |
| Reason (R): | Oxygen forms pπ - pπ multiple bonds due to its small size and small bond length but pπ - pπ bonding is not possible in sulphur. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is False. |
| 4. | Both (A) and (R) are False. |
Subtopic: Group 16 - Preparation, Properties & Uses |
73%
Level 2: 60%+
Hints
Identify the incorrect statement from the following:
| 1. | The acidic strength of HX (X=F, Cl, Br and I) follows the order: HF > HCI > HBr >HI |
| 2. | Fluorine exhibits - 1 oxidation state whereas other halogens exhibit +1, +3, +5 and +7 oxidation states also. |
| 3. | The enthalpy of dissociation of F2 is smaller than that of Cl2. |
| 4. | Fluorine is stronger oxidising agent than chlorine. |
Subtopic: Group 17 - Preparation, Properties & Uses |
71%
Level 2: 60%+
NEET - 2024
Hints
The reason behind carbon showing catenation property but lead does not is:
1. Due to the smaller size of C than that of Pb
2. Due to the smaller size of Pb than that of C
3. Due to the smaller ionization energy of C than that of Pb
4. Due to the inert pair effect
Subtopic: Carbon Family - Preparations, Properties & Uses |
73%
Level 2: 60%+
Hints
Links
Boric acid is polymeric due to-
1. Its acidic nature.
2. The presence of hydrogen bonds.
3. Its monobasic nature.
4. Its geometry.
Subtopic: Compounds of Boron- Preparations, Properties & Uses |
72%
Level 2: 60%+
Hints
Links
Select the element (M) whose trihalides cannot be hydrolysed to form [M(H2O)6]3+.
| 1. | Ga | 2. | In |
| 3. | Al | 4. | B |
Subtopic: Boron Family- Preparations, Properties & Uses |
75%
Level 2: 60%+
NEET - 2023
Hints
Select Question Set:
© 2025 GoodEd Technologies Pvt. Ltd.