CH₃CH₂CO-NH₂ can be converted into CH₃CH₂NH₂ in the presence of:

1. LiAlH₄ 

2. H₂/Pt

3. Sn/HCl 

4. NaOBr/OH^–

In addition to tertiary amine, what other product is produced in the below mentioned reaction?

In a set of reactions, propanoic acid yielded a compound (D).

\(CH_3CH_2COOH\ \text{(A)} \xrightarrow[]{SOCl_2}\ \text{(B)} \)
\(\ \xrightarrow[]{NH_3}\ \text{(C)}\ \xrightarrow[Br_2]{KOH}\ \text{(D)}\)

The formula for (D) is:

1. ${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2{\mathrm{NH}}_2$

2. ${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CONH}}_2$

3. ${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{NHCH}}_3$

4. ${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{NH}}_2$

The products A and B in the below mentioned reaction are:

1.		2.
3.		4.

Aniline undergoes the following reaction sequence to yield product D:

What is the formula of the product D?

1. $C_6{H}_{5}NHOH$

2. $C_6{H}_{5}NHC{H}_{2}C{H}_3$

3. $C_6{H}_{5}C{H}_{2}N{H}_2$

4. $C_6{H}_{5}C{H}_{2}OH$

Benzene diazonium chloride on reaction with aniline in the presence of dilute hydrochloric acid gives:

1.		2.
3.		4.

Consider the following reaction sequence:
  \(\small{\begin{aligned}\xrightarrow[]{{Sn/HCl}}\ A \ \xrightarrow[0-5\ ^\circ C]{NaNO_2/HCl}\ B \ \xrightarrow[]{HBF_4}\ C \ \xrightarrow[Cu\ \Delta]{NaNO_2}\ D\end{aligned}}\)

The major product D in the above-mentioned reaction is:

1.		2.
3.		4.

\(A \left(\right. C_{3} H_{9} N \left.\right) \) reacts with benzenesulfonyl chloride to give an insoluble salt in alkali.

The structure of compound (A) will be:

1.	\(\mathrm{CH_3CH_2CH_2NH_2} \)	2.	\(\mathrm{CH_3NHCH_2CH_3}\)
3.		4.	None of the above

Which of the following compounds, when reduced with lithium aluminium hydride, produces a secondary amine?

1. Nitroethane

2. Methylisocyanide

3. Acetamide

4. Methyl cyanide