Q. No.The oxo metal anions of the 3d series in which the metal exhibits an oxidation state equal to its group number is /are:
| 1. | 2. | ||
| 3. | 4. | All of these |
The correct statement regarding the element silver(Ag) is:
| 1. | It is a hard metal. |
| 2. | It is not a transition element. |
| 3. | It has a partially filled d orbital in a +2 oxidation state. Thus, it is a transition element. |
| 4. | None of the above |
The enthalpy of atomization of transition metals is high due to :
1. High effective nuclear charge
2. A large number of valence electrons
3. Very strong metallic bonds
4. All of the above
Find the set of ions that are coloured in aqueous solution.
2. Sc³āŗ, Mn²āŗ and Fe³āŗ
3. Ti³āŗ, V³āŗ, Mn²āŗ, Fe³āŗ and Co²āŗ
4. None of the above.
The correct statement(s) regarding the oxidation state of transition elements is/are:
1. The oxidation state can vary from +1 to +7
2. Variable oxidation states are possible.
3. Both (1) and (2)
4. None of the above
Mn2+ compounds are more stable than Fe2+ compounds towards oxidation in their +3 state because :
| 1. | 3d5 configuration is more stable than 3d6 configuration. |
| 2. | 3d6 configuration is more stable than 3d5 configuration. |
| 3. | 3p5 configuration is less stable than 3p6 configuration. |
| 4. | 3p6 configuration is less stable than 3p5 configuration. |
The consequence(s) of lanthanoid contraction is/are :
| 1. | Similarity in the properties of second and third transition series. |
| 2. | Separation of lanthanoids is difficult. |
| 3. | Variation in the basic strength of lanthanide hydroxides. |
| 4. | All of the above. |
The transition metals generally form coloured compounds due to :
| 1. | Absorption of radiation to promote an electron . |
| 2. | Presence of ligands, the d-orbitals split up into two sets of orbitals. |
| 3. | Energy required to promote an electron in d subshell is low. |
| 4. | All of the above. |
The reaction(s) involved in the preparation of potassium dichromate from iron chromite ore is/are:
| 1. | FeCr2O4 + NaOH + O2 → Na2CrO4 + Fe2O3 + H2O |
| 2. | Na2CrO4 + H2SO4 (conc.) → Na2Cr2O7 + Na2SO4 + H2O |
| 3. | Na2Cr2O7 + KCl→ K2Cr2O7 + NaCl |
| 4. | All of the above. |
| 1. | The number of oxidation states increases on moving from Sc to Mn. |
| 2. | The relative stability of the +2 oxidation state increases on moving from top to bottom. |
| 3. | The relative stability of the +2 oxidation state decreases on moving from top to bottom. |
| 4. | Both (1) and (2) |
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