# NEET Physics Waves Questions Solved

The ends of a stretched wire of length L are fixed at x = 0 and x = L. In one experiment, the displacement of the wire is ${y}_{1}=A\mathrm{sin}\left(\pi x/L\right)\mathrm{sin}\omega t$ and energy is E1, and in another experiment its displacement is ${y}_{2}=A\mathrm{sin}\left(2\pi x/L\right)\mathrm{sin}2\omega t$ and energy is E2. Then

(1) E2 = E1

(2) E2 = 2E1

(3) E2 = 4E1

(4) E2 = 16E1