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Q. No.A plant breeder crossed a pure bred tall plant having white flowers with a pure bred dwarf plant having blue flowers. He obtained 202 \(F_1\) progeny and found that they are all tall having blue flowers. Upon selfing these \(F_1\) plants he obtained a progeny of 2160 plants. Approximately how many of these likely to be short having blue flowers?
1. 1215
2. 405
3. 540
4. 135
Subtopic: Dihybrid Cross Analysis |
Level 4: Below 35%
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Given below is a karyotype of a human foetus obtained for screening to find any probable genetic disorder :
Based on the karyotype, the chromosomal disorder detected in unborn foetus and the consequent symptoms the child may suffer from are :
1. Turner's syndrome : Sterile ovaries, short stature
2. Down's syndrome : Gynecomastia, overall masculine stature
3. Turner's syndrome : Small round head, flat back of head
4. Down's syndrome : Furrowed tongue, short stature
Based on the karyotype, the chromosomal disorder detected in unborn foetus and the consequent symptoms the child may suffer from are :
1. Turner's syndrome : Sterile ovaries, short stature
2. Down's syndrome : Gynecomastia, overall masculine stature
3. Turner's syndrome : Small round head, flat back of head
4. Down's syndrome : Furrowed tongue, short stature
Subtopic: Non - Disjunction & Aneuploidy | Sex Aneuploidy - Turner & Klinefelter Syndrome |
73%
Level 2: 60%+
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In the dihybrid cross that was conducted by Morgan involving mating between parental generation for genes yellow bodied, white eyed female Drosophila and wild type male Drosophila, upto \(F_2\) generation is given below :
Study the result obtained of the \(F_2\) progeny. Select the correct option from the given choice for the \(F_2\) progeny.
1. Parental type, \(1.3 \%\) : Strength of linkage high
2. Recombinant types, \(1.3 \%\) : Strength of linkage high
3. Parental type \(98.7 \%\) : Strength of linkage high
4. Recombinant types, \(98.7 \%\) : Strength of linkage low
Study the result obtained of the \(F_2\) progeny. Select the correct option from the given choice for the \(F_2\) progeny.
1. Parental type, \(1.3 \%\) : Strength of linkage high
2. Recombinant types, \(1.3 \%\) : Strength of linkage high
3. Parental type \(98.7 \%\) : Strength of linkage high
4. Recombinant types, \(98.7 \%\) : Strength of linkage low
Subtopic: Chromosomal Basis of Inheritance: Introduction | Chromosomal Basis of Inheritance: Further Considerations |
62%
Level 2: 60%+
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Chromosomal aberrations are caused by:
1. Change in the structure of the gene
2. Change in the number of chromosomes
3. Change in the arrangement or position of genes
4. Change in the number or arrangement of genes in the chromosomes
1. Change in the structure of the gene
2. Change in the number of chromosomes
3. Change in the arrangement or position of genes
4. Change in the number or arrangement of genes in the chromosomes
Subtopic: Non - Disjunction & Aneuploidy |
55%
Level 3: 35%-60%
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1:2:1 phenotypic and genotypic ratio is found in:
1. Complementary genes.
2. Pseudo alleles.
3. Blending inheritance
4. Multiple alleles.
1. Complementary genes.
2. Pseudo alleles.
3. Blending inheritance
4. Multiple alleles.
Subtopic: Monohybrid Cross: Further Understanding |
54%
Level 3: 35%-60%
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Possibilities of the blood groups of the children in a family where the father is heterozygous for blood group A and the mother is heterozygous for blood group B would be:
1. Blood Group A and B
2. Blood Group A, B and O
3. Blood Group AB and O
4. Blood Group A, B, AB and O
1. Blood Group A and B
2. Blood Group A, B and O
3. Blood Group AB and O
4. Blood Group A, B, AB and O
Subtopic: Co-dominance |
85%
Level 1: 80%+
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| Assertion (A): | Turner's syndrome is generally not found in males. |
| Reason (R): | The disorder occurs due to monosomy. |
| 1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
| 3. | (A) is true but (R) is false. |
| 4. | (A) is false but (R) is true. |
Subtopic: Sex Aneuploidy - Turner & Klinefelter Syndrome |
Level 4: Below 35%
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Consider a test cross between a homozygous recessive yellow-seeded plant with a plant having an unknown seed. 50% of the offspring in the F1 generation have yellow seeds and 50% have green seeds.
Which of the following statements is/are TRUE about the cross?
1. The unknown seed is homozygous recessive for green.
2. The unknown seed is heterozygous for green.
3. All the offspring in the F2 generation will have green seeds.
4. All the offspring in the F2 generation will have yellow seeds.
1. Only 1.
2. Only 2
3. Only 1 and 4.
4. Only 2 and 3.
Which of the following statements is/are TRUE about the cross?
1. The unknown seed is homozygous recessive for green.
2. The unknown seed is heterozygous for green.
3. All the offspring in the F2 generation will have green seeds.
4. All the offspring in the F2 generation will have yellow seeds.
1. Only 1.
2. Only 2
3. Only 1 and 4.
4. Only 2 and 3.
Subtopic: Monohybrid Cross: Further Understanding |
73%
Level 2: 60%+
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In a cross between full green pods (FFGC) and constricted yellow pads (ffgg), the percentage of heterozygous dominant offsprings in F1 is:
1. \(25 \%\).
2. \(50 \%\).
3. \(75 \%\).
4. \(100 \%\).
1. \(25 \%\).
2. \(50 \%\).
3. \(75 \%\).
4. \(100 \%\).
Subtopic: Dihybrid Cross: General Consideration |
59%
Level 3: 35%-60%
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A single gene is usually seen to exhibit a single phenotypic expression. Pleiotropic genes. however, can impact multiple phenotypic expressions.
Which of these genetic disorders have multiple phenotypic expressions being impacted by a change in a single gene?
1. Thalassemia
2. Haemophilia
3. Phenylketonuria
4. Down's syndrome
Which of these genetic disorders have multiple phenotypic expressions being impacted by a change in a single gene?
1. Thalassemia
2. Haemophilia
3. Phenylketonuria
4. Down's syndrome
Subtopic: Polygenic Inheritance & Pleiotropy |
88%
Level 1: 80%+
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