- 1(current)
Q. No.The gene for the enzyme Phenylalanine hydroxylase is located on chromosome:
1. 7
2. 11
3. 12
4. X
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Identify the incorrectly matched pair:
|
|
Mendelian disorder |
Gene present on chromosome |
|
1. |
Sickle cell anemia |
11 |
|
2. |
Phenylketonuria |
12 |
|
3. |
Cystic fibrosis |
6 |
|
4. |
Huntington’s disease |
4 |
In a human population, 1 in 10,000 are affected with an autosomal recessive disorder. What proportion of that human population is likely to be a carrier of the recessive allele?
1. approximately 0.02
2. approximately 0.19
3. approximately 0.98
4. approximately 0.2
Match each item in COLUMN I [genetic disorder] with its description in Column II and select the correct answer from the codes given:
|
|
COLUMN I |
|
COLUMN II |
|
A. |
Huntington's disease |
a. |
Inability to metabolize certain lipids, affecting proper brain development and death in early childhood. |
|
B. |
Tay-Sachs disease |
b. |
Caused by a dominant single gene defect and generally does not appear until the individual is 35-45 years of age |
|
C. |
phenylketonuria |
c. |
Effects of this recessive disorder can be completely overcome by regulating the diet of the affected individual |
|
D. |
Cystic fibrosis |
d. |
This results from a defect in membrane proteins that normally function in chloride ion transport |
Codes:
A B C D
1. a b c d
2. b a c d
3. a b d c
4. b a d c
An abnormal human baby with 'XXX' sex chromosomes was born due to :
1. formation of abnormal ova in the mother
2. fusion of two ova and one sperm
3. fusion of two sperms and one ovum
4. formation of abnormal sperms in the father
One of the genes present exclusively on the X-chromosome in humans is concerned with
1. Baldness
2. Red-green color blindness
3. Facial hair/moustaches in males
4. Night blindness
Study the pedigree chart given below:
What does it show?
| 1. | Inheritance of a sex-linked inborn error of metabolism |
| 2. | Inheritance of a condition like phenylketonuria as an autosomal recessive trait |
| 3. | The pedigree chart is wrong as this is not possible |
| 4. | Inheritance of a recessive sex-linked disease like haemophilia |
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A normal woman whose father was colour blind is married to normal visioned man. Their sons would be
1. 75% colour blind
2. 50% colour blind
3. 100% colour blind
4. All normal.
If a colourblind man marries a woman who is homozygous for normal colour vision, the probability of their son being colourblind is:
1. 0
2. 0.5
3. 0. 75
4. 1
- 1(current)
Q. No.
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