A man who is an achondroplastic dwarf with normal vision marries a color-blind woman of normal height. The man's father was six feet tall, and both the woman's parents were of average height. Achondroplastic dwarfism is autosomal dominant, and red-green color blindness is X- linked recessive. What proportion of their sons would be color-blind and of normal height?

1. All 2. None
3. Half 4. One out of four

Subtopic:  Sex Linked Inheritance: Characteristics |
 51%

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On the basis of information given in the pedigree, if II 3 marries a hemophilic man, what is the probability that her first child will be normal?

   

1. 1/4 2. 1/2
3. 3/4 4. 0

Subtopic:  Pedigree Analysis: Problem Solving | Pedigree Analysis: More Examples |
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If a chiasma forms between the loci of genes A and B in 20 % of the tetrads of an individual of genotype AB/ab, the percentage of gametes expected to be Ab is:

1. 40 2. 20
3. 10 4. 5

Subtopic:  Understanding Linkage | Linkage Types | Recombination & Gene Mapping |

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A dihybrid test cross shows a frequency of recombination of 50 %. The best explanation will be:

1. The two genes are likely to be located on different chromosomes
2. All of the offspring have combinations of traits that match one of the two parents
3. The genes are located on sex chromosomes
4. Abnormal meiosis has occurred

Subtopic:  Understanding Linkage | Linkage Types |
 57%
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A woman receives her X chromosomes from:

1. her mother only

2. her father only

3. both her mother and her father

4. extranuclear DNA in her mother's egg

Subtopic:  Sex Determination |
 80%
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The frequency of crossing over between any two linked genes will be:

1. Higher if they are recessive
2. Dependent on how many alleles there are
3. Determined by their relative dominance
4. Proportional to the distance between 
Subtopic:  Understanding Linkage | Linkage Types | Recombination & Gene Mapping |
 79%
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The disease inheritance pattern exemplified in the given pedigree analysis can be:
 

1. Hemophilia 2. Red-green colour blindness
3. Phenyl ketonuria 4. Polydactyly
Subtopic:  Pedigree Analysis: More Examples |
 71%
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Consider the following statements:

I: People affected by phenylketonuria are unable to convert tyrosine to phenylalanine.
II: Alzheimer’s disease results from the accumulation of amyloid protein plaques in the brain.
III: Klinefelter’s and Turner’s syndromes are the result of nondisjunction of the sex chromosomes in either of the sexes.

Which of the above statements are true?

1. I and II only 2. I and III only
3. II and III only 4. I, II, and III
Subtopic:  Mendelian Disorders | Non - Disjunction & Aneuploidy |
 70%
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Which of the following would not be a feature seen in a patient with the following karyotype?
   
1. Many loops on fingertips
2. Congenital heart disease
3. Big and wrinkled tongue
4. Mucus clogging of airways

Subtopic:  Non - Disjunction & Aneuploidy |
 69%
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Given below is the initial amino acids of the beta chain of a haemoglobin molecule. What will be true about this haemoglobin molecule?

1. The RBCs carrying this molecule will undergo sickling at a high oxygen tension
2. The RBCs carrying this molecule will undergo sickling at a low oxygen tension
3. There will be a quantitative decrease in the synthesis of this molecule
4. This is the normal beta chain of the haemoglobin molecule
Subtopic:  Mendelian Disorders: Sickle Cell Anemia |
 58%
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