Figure shows the connections of two ideal diodes and two capacitors C and 2C. A 120 volt battery is connected to the input terminals with a at positive potential and b at lower potential. The output voltage across cd is

                   

1.  60 V

2.  40 V

3.  30 V

4.  20 V

In the circuit shown in the figure, the input voltage V_i is 20 V, V_BE = 0, and V_CE = 0. The values of I_B, I_C and $\beta$ are given by:
           

1. ${\mathrm{I}}_{\mathrm{B}}$ $=$ $40$ $\mathrm{\mu A},$ ${\mathrm{I}}_{\mathrm{c}}$ $=$ $10$ $\mathrm{mA},$ $\mathrm{\beta }$ $=$ $250$

2. ${\mathrm{I}}_{\mathrm{B}}$ $=$ $25$ $\mathrm{\mu A},$ ${\mathrm{I}}_{\mathrm{c}}$ $=$ $5$ $\mathrm{mA},$ $\mathrm{\beta }$ $=$ $200$

3. ${\mathrm{I}}_{\mathrm{B}}$ $=$ $20$ $\mathrm{\mu A},$ ${\mathrm{I}}_{\mathrm{c}}$ $=$ $5$ $\mathrm{mA},$ $\mathrm{\beta }$ $=$ $250$

4. ${\mathrm{I}}_{\mathrm{B}}$ $=$ $40$ $\mathrm{\mu A},$ ${\mathrm{I}}_{\mathrm{c}}$ $=$ $5$ $\mathrm{mA},$ $\mathrm{\beta }$ $=$ $125$

The given circuit has two ideal diodes connected as shown in the figure below. The current flowing through the resistance \(R_1\) will be:
   
1. \(2.5~\text{A}\)
2. \(10.0~\text{A}\)
3. \(1.43~\text{A}\)
4. \(3.13~\text{A}\)

Transfer characteristics [output voltage (${\mathrm{V}}_{\mathrm{o}}$) vs input voltage (${\mathrm{V}}_{\mathrm{i}}$)] for a base biased transistor in CE configurations are as shown in the figure. For using the transistor as a switch, it is used:

1. In region III

2. Both in the region (I) and (III)

3. In region II

4. In region I