In a common emitter transistor, the current gain is 80. What is the change in collector current, when the change in base current is 250 μ
(1) 80 × 250 μA

(2) (250 – 80) μA

(3) (250 + 80) μA

(4) 250/80 μA

 83%
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Least doped region in a transistor 

(1) Either emitter or collector

(2) Base

(3) Emitter

(4) Collector

 86%
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The symbol given in figure represents 

(1) NPN transistor

(2) PNP transistor

(3) Forward biased PN junction diode

(4) Reverse biased NP junction diode

 77%
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The part of a transistor which is heavily doped to produce a large number of majority carriers is-

1. Base                 

2. Emitter

3. Collector           

4. None of these

 81%
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In NPN transistor the collector current is 10 mA. If 90% of electrons emitted reach the collector, then

(1) Emitter current will be 9 mA

(2) Emitter current will be 11.1 mA

(3) Base current will be 0.1 mA

(4) Base current will be 0.01 mA

 79%
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The combination of ‘NAND’ gates shown here under (figure) are equivalent to

1. An OR gate and an AND gate respectively
2. An AND gate and a NOT gate respectively
3. An AND gate and an OR gate respectively
4. An OR gate and a NOT gate respectively.

Subtopic:  Logic gates |
 70%
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 The logic behind the ‘NOR’ gate is that it gives

(1) High output when both the inputs are low

(2) Low output when both the inputs are low

(3) High output when both the inputs are high

(4) None of these

Subtopic:  Logic gates |
 84%
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The Boolean equation of NOR gate is 

(1) C = A + B

(2) C=A+B¯ 

(3) C=A·B 

(4) C=A.B¯

Subtopic:  Logic gates |
 89%
From NCERT
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Which of the following logic gate is a universal gate?
1. OR
2. NOT
3. AND
4. NOR

Subtopic:  Logic gates |
 76%
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Let nP and ne be the number of holes and conduction electrons respectively in a semiconductor. Then

(1) nP>ne in an intrinsic semiconductor

(2) nP=ne in an extrinsic semiconductor

(3) nP=ne in an intrinsic semiconductor

(4) ne<nP in an intrinsic semiconductor

Subtopic:  Types of Semiconductors |
 83%
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