Q. No.
A compound that form two stereoisomer is -
(I)
(II)
(III)
(IV)
(1)I only
(2) I and II
(3) III and IV
(4) All of these
Three arrangements are shown for the complex . Which one is wrong statement?
1. I and II are geometrical isomers
2. II and III are optically active isomers
3. I and III are optically active isomers
4. II and III are geometrical isomers
A complex with the composition is found to have no geometrical isomers. The possible structures (s) of the complex is (Where A and B are monodentate ligands)
(1) Tetrahedral
(2) Square planar
(3) Both (a) and (b)
(4) Cannot be predicted
Complexes formed in the following methods are:
(I) Mond's process for purification of nickel
(II) Removal of unreacted AgBr from photographic plate
(III) Removal of lead poisoning from the body
Options are as follows:
The correct name for the complex ion is:
1. chlorobis(ethylenediamine)nitrito-O-cobaltate(III) ion
2. chlorodiethyldiaminenitrito-O-cobalt(III) ion
3. chloronitrito-O-diethyldiamine cobaltate (III) ion
4. chlorobis (ethylenediamine)nitrito-O-cobalt (III) ion
is diamagnetic because:
1. Mn metal is paramagnetic in free state
2. Mn is in +1 oxidation state in this complex
3. NO is present as positive ligand
4. All of the above
Choose the correct option regarding the following complex compound which follows (F) and does not follow (NF) the Sidgwick EAN rule:
(I) (II)
(III) (IV)
(I) (II) (III) (IV) (I) (II) (III) (IV)
(a) NF NF NF NF (b) F F NF F
(c) NF NF F F (d) NF NF F NF
The electronic arrangement of an octahedral complex with a configuration, if ∆0 < pairing energy is:
1.
2.
3.
4.
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