$\left[\mathrm{Mn}\right(\mathrm{CO}{)}_4\mathrm{NO}]$ is diamagnetic because:

1. Mn metal is paramagnetic in free state

2. Mn is in +1 oxidation state in this complex

3. NO is present as positive ligand

4. All of the above

 

Choose the correct option regarding the following complex compound which follows (F) and does not follow (NF) the Sidgwick EAN rule:

(I) $\left[\right({\mathrm{Ph}}_3\mathrm{P}{)}_2{\mathrm{PdCl}}_2{\mathrm{PdCl}}_2]$                     (II) $\left[\mathrm{NiBrCl}\right(\mathrm{en}\left)\right]$

(III) ${\mathrm{Na}}_4\left[\mathrm{Fe}\right(\mathrm{CN}{)}_5\mathrm{NOS}]$                       (IV) $\mathrm{Cr}\left(\mathrm{CO}{)}_3\right(\mathrm{NO}{)}_2$

        (I)    (II)    (III)    (IV)                       (I)    (II)    (III)     (IV) 

(a)    NF   NF      NF       NF                 (b)    F       F        NF        F

(c)     NF   NF      F          F                  (d)   NF      NF      F          NF 

Which of the following species can act as reducing agent ?

(1) $\left[\mathrm{Co}\right(\mathrm{CO}{)}_4{]}^{-}$     

(2) $\mathrm{Mn}(\mathrm{CO}{)}_6$       

(3) $\mathrm{Mn}(\mathrm{CO}{)}_5$       

(4) $\mathrm{Cr}(\mathrm{CO}{)}_6$

The electronic arrangement of an octahedral complex with a ${\mathrm{d}}^4$ configuration, if ∆₀ < pairing energy is:

1. ${\mathrm{t}}_{2\mathrm{g}}^4{\mathrm{e}}_{\mathrm{g}}^0$                       

2. ${\mathrm{e}}_{\mathrm{g}}^4{\mathrm{t}}_{2\mathrm{g}}^0$               

3. ${\mathrm{t}}_{2\mathrm{g}}^3{\mathrm{e}}_{\mathrm{g}}^1$           

4. ${\mathrm{e}}_{\mathrm{g}}^2{\mathrm{t}}_{2\mathrm{g}}^2$

Which of the following statement is not correct ?

(a) Bis(glycinato)Zinc(II) is optically active

(b) $[{\mathrm{NiCl}}_4{]}^{2-<mspace\; width="1em"></mspace>}\mathrm{and}<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>[{\mathrm{PtCl}}_4{]}^{2-}$ have different shape

(c) $\left[\mathrm{Ni}\right(\mathrm{CN}{)}_4{]}^{4-}$ is square planar complex

(d) $\left[\mathrm{Ni}\right(\mathrm{CN}{)}_4{]}^{2-<mspace\; width="1em"></mspace>}\mathrm{and}<mspace\; width="1em"></mspace>\left[\mathrm{Ni}\right(\mathrm{CO}{)}_4]$ have the same magnetic moment

Give the correct of initial T or F for following statements. Use T is statement is true and F if it is false

(I) Co(III) is stabilised in presence of weak ligands , while Co(II) is stabilised in presence of strong field ligand.

(II) Four coordinated complexes of Pd(II) and Pt(II) are diamagnetic and square planar.

(III) $\left[\mathrm{Ni}\right(\mathrm{CN}{)}_4{]}^{4-}$ ion and $\left[\mathrm{Ni}\right(\mathrm{CO}{)}_4]$ are diamagnetic tetrahedral and square planar.

(IV) ${\mathrm{Ni}}^{2+}$ ion does not form inner orbital octahedral complexes.

(1) TFTF                                   

(2) TTTF

(3) TTFT                                   

(4) FTFT

Match List-I with List-II and select the correct answer using the codes given below :

                      List-I                                              List-II

(I) $[{\mathrm{FeF}}_6{]}^{3-}$                                                   (A) 1.73 BM

(II) $\left[\mathrm{Ti}\right({\mathrm{H}}_2\mathrm{O}{)}_6{]}^{3+}$                                             (B) 5.93 BM

(III) $\left[\mathrm{Cr}\right({\mathrm{NH}}_3{)}_6{]}^{3+}$                                            (C) 0.00 BM

(IV) $\left[\mathrm{Ni}\right({\mathrm{H}}_2\mathrm{O}{)}_6{]}^{2+}$                                             (D) 2.83 BM

(V)  $\left[\mathrm{Fe}\right(\mathrm{CN}{)}_6{]}^{4-}$                                               (E) 3.88 BM

          (I)    (II)   (III)   (IV)   (V)                       (I)    (II)   (III)   (IV)   (V) 

(a)      B      A       C       D      E                  (b)    B      A       E       D      C

(c)       B     C       D       E      A                 (d)     D     E       A       B       C  

Set of d-orbitals which is used by central metal during formation of ${\mathrm{MnO}}_4^{-}$?

(1) ${\mathrm{d}}_{{\mathrm{x}}^2-{\mathrm{y}}^2<mspace\; width="1em"></mspace>},{\mathrm{d}}_{{\mathrm{z}}^{2<mspace\; width="1em"></mspace>}},{\mathrm{d}}_{\mathrm{xy}}$                   

(2) ${\mathrm{d}}_{\mathrm{xy}}<mspace\; width="1em"></mspace>,<mspace\; width="1em"></mspace>{\mathrm{d}}_{\mathrm{yz}}<mspace\; width="1em"></mspace>,<mspace\; width="1em"></mspace>{\mathrm{d}}_{\mathrm{xz}}$

(3) ${\mathrm{d}}_{{\mathrm{x}}^2-{\mathrm{y}}^2}<mspace\; width="1em"></mspace>,<mspace\; width="1em"></mspace>{\mathrm{d}}_{\mathrm{xy}}<mspace\; width="1em"></mspace>,<mspace\; width="1em"></mspace>{\mathrm{d}}_{\mathrm{xz}}$                   

(4) ${\mathrm{d}}_{{\mathrm{x}}^2-{\mathrm{y}}^2}<mspace\; width="1em"></mspace>,<mspace\; width="1em"></mspace>{\mathrm{d}}_{z^2}<mspace\; width="1em"></mspace>,<mspace\; width="1em"></mspace>{\mathrm{d}}_{\mathrm{xz}}$

${\mathrm{FeSO}}_4$ is a very good absorber for NO, the new compound formed by this process is found to contain number of unpaired electrons:

(1) 4         

(2) 5           

(3) 3         

(4) 6

$\mathrm{A}\left[\mathrm{M}\right({\mathrm{H}}_2\mathrm{O}{)}_6{]}^{2+}$ complex typically absorbs at around 600 nm. It is allowed to react with ammonia to form a new complex $\left[\mathrm{M}\right({\mathrm{NH}}_3{)}_6{]}^{2+}$ that should have absorption at :

(1) 800 nm         (2) 580 nm       (3) 620 nm      (4)  320 nm