The labeled -O¹⁸ will be:


1. H₂O

2. Methyl benzoate

3. Both 1 and 2

4. Benzoic acid

Product (A) in the below mentioned reaction is:
 

1.

2.

3.

4.

Which of the following compounds is most prone to oxidation?
 

1.	\(\mathrm{CH}_3-\mathrm{CHOH}-\mathrm{CH}_3\)	2.
3.	\(\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{O}-\mathrm{CH}_2-\mathrm{CH}_3\)	4.

Which of the following react with HBr at faster rate?

$\stackrel{{\mathrm{LiAlH}}_4}{\to }$(A) Major; Product (A) is:   

(a) 

(b) 

(c) 

(d) 

$\stackrel{{\mathrm{H}}_2{\mathrm{CrO}}_4}{\to }$(A) Product (A) is:   

(a) No reaction

(b) 

(c) 

(d) 

Consider the following alcohols,

(I)  (II) 

(III) (IV) 

The order of decreasing reactivities of these alcohols towards nucleophilic substitution with HBr is:-

(a) III>I>IV>II

(b) III>I>II>IV

(c) I>III>IV>II

(d) I>III>II>IV

$\underset{\left(2\right)<mspace\; width="1em"></mspace>{\mathrm{H}}^{+},<mspace\; width="1em"></mspace>{\mathrm{H}}_2\mathrm{O}<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>}{\overset{\left(1\right)<mspace\; width="1em"></mspace>\mathrm{EtLi}<mspace\; width="1em"></mspace>(3.5<mspace\; width="1em"></mspace>\mathrm{eq})}{\to }}<mspace\; width="1em"></mspace>\left(\mathrm{A}\right)<mspace\; width="1em"></mspace>65\%<mspace\; width="1em"></mspace>\mathrm{Yield}<mspace\; width="1em"></mspace>$; Chemist added extra 0.5 mole of Et-Li in above reaction to obtain product (A), which is ?