# NEET Questions Solved

PMT - 1976

Two resistances are joined in parallel whose resultant is $\frac{6}{8}$ ohm. One of the resistance wire is broken and the effective resistance becomes 2Ω. Then the resistance in ohm of the wire that got broken was

(1) 3/5

(2) 2

(3) 6/5

(4) 3

(3) If resistances are ${R}_{1}$ and ${R}_{2}$ then $\frac{{R}_{1}{R}_{2}}{{R}_{1}+{R}_{2}}=\frac{6}{8}$ …..(i)

Suppose ${R}_{2}$ is broken then ${R}_{1}=2\Omega$  …..(ii)

On solving equations (i) and (ii) we get ${R}_{2}=6/5\text{\hspace{0.17em}}\Omega$

Difficulty Level:

• 14%
• 23%
• 58%
• 7%
Crack NEET with Online Course - Free Trial (Offer Valid Till August 23, 2019)