# NEET Questions Solved

Four wires of equal length and of resistances 10 ohms each are connected in the form of a square. The equivalent resistance between two opposite corners of the square is

(1) 10 ohm

(2) 40 ohm

(3) 20 ohm

(4) 10/4 ohm

(1) According to the problem, we arrange four resistance as follows

Equivalent resistance $=\frac{20×20}{40}=10\Omega$

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