Q. No.A pendulum takes \(35.2\) seconds to complete \(10\) oscillations. What is the time period of the pendulum, expressed with the correct number of significant figures?
1. \(3.52~\text s\)
2. \(3.5~\text s\)
3. \(3.520~\text s\)
4. \(3.6~\text s\)
1. \(3.52~\text s\)
2. \(3.5~\text s\)
3. \(3.520~\text s\)
4. \(3.6~\text s\)
1. \(\text{Power}\)
2. \(\text{Work} \times \text{Distance}\)
3. \(\text{Force}\)
4. \(\text{Work} \times \text{Time}\)
1. \((7\pm0.2)~\text{m}\)
2. \((7\pm0.8)~\text{m}\)
3. \((7\pm0.6)~\text{m}\)
4. \((7\pm0.1)~\text{m}\)
| 1. | both units and dimensions |
| 2. | units but no dimensions |
| 3. | dimensions but no units |
| 4. | no units and no dimensions |
1. electric permittivity
2. magnetic flux
3. self-inductance
4. magnetic permeability
1. \(14\times10^{2}\)
2. \(138\times10^{1}\)
3. \(1382\)
4. \(1382.5\)
| List-I | List-II | ||
| (a) | Gravitational constant (\(G\)) | (i) | \([{L}^2 {~T}^{-2}] \) |
| (b) | Gravitational potential energy | (ii) | \([{M}^{-1} {~L}^3 {~T}^{-2}] \) |
| (c) | Gravitational potential | (iii) | \([{LT}^{-2}] \) |
| (d) | Gravitational intensity | (iv) | \([{ML}^2 {~T}^{-2}]\) |
| (a) | (b) | (c) | (d) | |
| 1. | (iv) | (ii) | (i) | (iii) |
| 2. | (ii) | (i) | (iv) | (iii) |
| 3. | (ii) | (iv) | (i) | (iii) |
| 4. | (ii) | (iv) | (iii) | (i) |
When the circular scale of a screw gauge completes \(2\) rotations, it covers \(1\) mm over the pitch scale. The total number of circular scale divisions is \(50.\) The least count of the screw gauge in metres is:
1. \(10^{-4}\)
2. \(10^{-5}\)
3. \(10^{-2}\)
4. \(10^{-3}\)
The determination of the value of acceleration due to gravity \((g)\) by simple pendulum method employs the formula,
\(g=4\pi^2\frac{L}{T^2}\)
The expression for the relative error in the value of \(g\) is:
1. \(\frac{\Delta g}{g}=\frac{\Delta L}{L}+2\Big(\frac{\Delta T}{T}\Big)\)
2. \(\frac{\Delta g}{g}=4\pi^2\Big[\frac{\Delta L}{L}-2\frac{\Delta T}{T}\Big]\)
3. \(\frac{\Delta g}{g}=4\pi^2\Big[\frac{\Delta L}{L}+2\frac{\Delta T}{T}\Big]\)
4. \(\frac{\Delta g}{g}=\frac{\Delta L}{L}-2\Big(\frac{\Delta T}{T}\Big)\)
1. \(0.1~\text{mm}\)
2. \(0.909~\text{mm}\)
3. \(1.1~\text{mm}\)
4. \(0.09~\text{mm}\)
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