Select Question Set:
Q. No.A graph is plotted by taking kinetic energy along the \(\mathrm{y}\)-axis and speed along the \(\mathrm{x}\)-axis for a constant mass. The slope of the graph at an instant represents:
| 1. | mass | 2. | velocity |
| 3. | momentum | 4. | acceleration |
Subtopic: Concept of Work |
64%
Level 2: 60%+
Please attempt this question first.
Hints
Please attempt this question first.
Given below are two statements:
| Assertion (A): | Work done by friction on a body sliding down an inclined plane is negative. |
| Reason (R): | Work done is less than zero if the angle between force and displacement is acute or both are in the same direction. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is False. |
| 4. | Both (A) and (R) are False. |
Subtopic: Concept of Work |
78%
Level 2: 60%+
Hints
A car moves on an inclined plane and covers \(10\) km path under the action of a horizontal force of \(5\) N. The work done on the car is \(25\) kJ. The inclination of the plane to horizontal is:
1. \(75^\circ\)
2. \(60^\circ\)
3. \(45^\circ\)
4. \(30^\circ\)
1. \(75^\circ\)
2. \(60^\circ\)
3. \(45^\circ\)
4. \(30^\circ\)
Subtopic: Work done by constant force |
81%
Level 1: 80%+
Please attempt this question first.
Hints
Please attempt this question first.
Unlock IMPORTANT QUESTION
This question was bookmarked by 5 NEET 2025 toppers during their NEETprep journey. Get Target Batch to see this question.
✨ Perfect for quick revision & accuracy boost
Buy Target Batch
Access all premium questions instantly
A small block of mass \(m\) lies on a frictionless wedge of mass \(M,\) which is pushed horizontally to the right by means of a constant force \(F\). There is no relative motion between the block and the wedge. Let the work done by \(F\) on \(M\) be \(W_F\). The work done by the normal force (between \(M\) & \(m\)) on \(m\) be \(W_m\). Both are measured for the same time interval.
Then:
Then:
| 1. | \(\dfrac{W_F}{M}=\dfrac{W_m}{m}\) | 2. | \(W_F\cdot M=W_m\cdot m\) |
| 3. | \(\dfrac{W_F}{M+m}=\dfrac{W_m}{m}\) | 4. | \(\dfrac{W_F}{M}=\dfrac{W_m}{m+M}\) |
Subtopic: Work done by constant force |
62%
Level 2: 60%+
Please attempt this question first.
Hints
Please attempt this question first.
A constant force, \(\vec F=2\hat i-\hat j+5\hat k\) N acts on a body to move it along the \(x\)-axis. The work done by the force to move it by \(2\) m along the \(x \)-axis will be:
| 1. | \(12\) J | 2. | \(16\) J |
| 3. | \(0\) | 4. | \(4\) J |
Subtopic: Work done by constant force |
89%
Level 1: 80%+
Please attempt this question first.
Hints
Please attempt this question first.
If a force \(F\) applied on an object moving along the \(\mathrm{y}\)-axis varies with the y-coordinate as \(F=3+2y^{2}. \) The work done in displacing the body from \(y=2\) m to \(y=5\) m is:
1. \(87\) J
2. \(0 \)
3. \(57\) J
4. \(72\) J
1. \(87\) J
2. \(0 \)
3. \(57\) J
4. \(72\) J
Subtopic: Work Done by Variable Force |
84%
Level 1: 80%+
JEE
Please attempt this question first.
Hints
Please attempt this question first.
A force \(F\) acting on an object varies with distance \(x\) as shown below:
The force is in Newton and \(x\) is in meters. The work done by the force in moving the object from \(x = 0\) to \(x = 6\) m is:
| 1. | \(18.0\) J | 2. | \(13.5\) J |
| 3. | \(4.5\) J | 4. | \(9.0\) J |
Subtopic: Work Done by Variable Force |
92%
Level 1: 80%+
AIPMT - 2005
Hints
\(300\) J of work is done in sliding a \(2\) kg block up an inclined plane of height \(10\) m. Taking \(g=10 \mathrm{~m} / \mathrm{s}^{2}\), work done against friction is:
1. \(1000\) J
2. \(200\) J
3. \(100\) J
4. zero
1. \(1000\) J
2. \(200\) J
3. \(100\) J
4. zero
Subtopic: Work Done by Variable Force |
81%
Level 1: 80%+
Please attempt this question first.
Hints
Please attempt this question first.
A particle experiences a variable force \(\vec F = (4x \hat i + 3y^2 \hat j)\) in a horizontal x-y plane. Assume distance in meters and force is in newton. If the particle moves from point \((1,2)\) to point \((2,3)\) in the x-y plane, the kinetic energy changes by:
1. \(50.0\) J
2. \(12.5\) J
3. \(25.0\) J
4. \(0\)
1. \(50.0\) J
2. \(12.5\) J
3. \(25.0\) J
4. \(0\)
Subtopic: Work Energy Theorem |
81%
Level 1: 80%+
JEE
Please attempt this question first.
Hints
Please attempt this question first.
A body of mass \(8\) kg and another of mass \(2\) kg are moving with equal kinetic energy. The ratio of their respective momenta will be:
1. \(1:1\)
2. \(2:1\)
3. \(1:4\)
4. \(4:1\)
1. \(1:1\)
2. \(2:1\)
3. \(1:4\)
4. \(4:1\)
Subtopic: Work Energy Theorem |
84%
Level 1: 80%+
JEE
Please attempt this question first.
Hints
Please attempt this question first.
Select Question Set:
© 2025 GoodEd Technologies Pvt. Ltd.