A cup of coffee cools from \(90^{\circ}\text{C}\) to \(80^{\circ}\text{C}\) in \(t\) minutes, when the room temperature is \(20^{\circ}\text{C}.\) The time taken by a similar cup of coffee to cool from \(80^{\circ}\text{C}\) to \(60^{\circ}\text{C}\) at room temperature same at \(20^{\circ}\text{C}\) is:

1. \(\dfrac{10}{13}t\) 2. \(\dfrac{5}{13}t\)
3. \(\dfrac{13}{10}t\) 4. \(\dfrac{13}{5}t\)

Subtopic:  Newton's Law of Cooling |
 66%
Level 2: 60%+
NEET - 2021
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Two conducting slabs of heat conductivity \(K_{1} ~\text{and}~K_{2}\) are joined as shown in figure. If the temperature at the ends of the slabs are \(\theta_{1}~\text{and}~\theta_{2} \ (\theta_{1}   >   \theta_{2} ),  \) then the final temperature \( \left(\theta\right)_{m} \) of the junction will be:

                

1. \(\frac{K_{1} \theta_{1}   +   K_{2} \theta_{2}}{K_{1}   +   K_{2}}\) 2. \(\frac{K_{1} \theta_{2}   +   K_{2} \theta_{1}}{K_{1}   +   K_{2}}\)
3. \(\frac{K_{1} \theta_{2}   +   K_{2} \theta_{1}}{K_{1}   -   K_{2}}\) 4. None
Subtopic:  Conduction |
 86%
Level 1: 80%+
AIPMT - 1999
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A slab of stone with an area \(0.36~\text{m}^{2}\) and thickness of \(0.1~\text{m}\) is exposed on the lower surface to steam at \(100​​^\circ\text{C}.\) A block of ice at \(0^{\circ}\text{C}\) rests on the upper surface of the slab. In one hour \(4.8~\text{kg}\) of ice is melted. The thermal conductivity of the slab will be:
(Given latent heat of fusion of ice \(= 3.36\times10^{5}~\text{JKg}^{-1}\))
1. \(1.29~\text{J/m/s/}^{\circ}\text{C}\)
2. \(2.05~\text{J/m/s/}^{\circ}\text{C}\)
3. \(1.02~\text{J/m/s/}^{\circ}\text{C}\)
4. \(1.24~\text{J/m/s/}^{\circ}\text{C}\)

Subtopic:  Conduction |
 62%
Level 2: 60%+
AIPMT - 2012
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The temperature at which the Celsius and Fahrenheit thermometers agree (to give the same numerical value) is:

1. \(-40^\circ\) 2. \(40^\circ\)
3. \(0^\circ\) 4. \(50^\circ\)
Subtopic:  Temperature and Heat |
 86%
Level 1: 80%+
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Three stars \(A,\) \(B,\) and \(C\) have surface temperatures \(T_A,~T_B\) and \(T_C\) respectively. Star \(A\) appears bluish, star \(B\) appears reddish and star \(C\) yellowish. Hence:
1. \(T_A>T_B>T_C\)
2. \(T_B>T_C>T_A\)
3. \(T_C>T_B>T_A\)
4. \(T_A>T_C>T_B\)
Subtopic:  Wien's Displacement Law |
 71%
Level 2: 60%+
NEET - 2020
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Two spheres \(A\) and \(B\) of same material having radius \(8\) cm and \(4\) cm are maintained at temperatures \(127^{\circ}\text{C}\) and \(527^{\circ}\text{C}\) respectively. The ratio of energy radiated by \(A\) and \(B\) is:
1. \(1:4\)
2. \(3:1\)
3. \(1:2\)
4. \(6:1\)
Subtopic:  Stefan-Boltzmann Law |
 84%
Level 1: 80%+
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Which of the curves in the figure represents the relation between Celsius and Fahrenheit temperature?

1. 2.
3. 4.
Subtopic:  Temperature and Heat |
 72%
Level 2: 60%+
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A liquid \(P\) of mass \(M\) and specific heat capacity \(S\) is at temperature \(2T.\) If another liquid \(Q\) of specific heat capacity \(1.5\) times liquid \(P\) at a temperature of \(\dfrac{T}{3}\) is added to it, the resultant temperature will be:
1. \(\dfrac{4T}{5}\) 2. \(T\)
3. \(\dfrac{T}{2}\) 4. \(\dfrac{5T}{4}\)
Subtopic:  Calorimetry |
 77%
Level 2: 60%+
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A radiation blackbody has the shape of a sphere of radius \(r.\) Its surface is at a temperature \(T\) (in Kelvin). If the temperature is doubled and the radius is halved, the total rate of radiation emitted from the body:
1. increases by a factor of \(4\)
2. increases by a factor of \(2\)
3. remains unchanged
4. decreases by a factor of \(2\) 
Subtopic:  Stefan-Boltzmann Law |
 82%
Level 1: 80%+
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Given below are two statements: 
Assertion (A): In a pressure cooker the water is brought to a boil. The cooker is then removed from the stove. Now on removing the lid of the pressure cooker, the water starts boiling again.
Reason (R): The impurities in water bring down its boiling point.
 
1. Both (A) and (R) are True and (R) is the correct explanation of (A).
2. Both (A) and (R) are True but (R) is not the correct explanation of (A).
3. (A) is True but (R) is False.
4. Both (A) and (R) are False.
Subtopic:  Calorimetry |
 50%
Level 3: 35%-60%
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