Camphor is often used in molecular mass determination because:

1. It has a very high cryoscopic constant

2. It is volatile

3. It is a solvent for organic substances

4. It is readily available 

Subtopic:  Introduction & Colligative properties |
Level 3: 35%-60%
AIPMT - 2004
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Which colligative property provides the most accurate method for determining the molecular weight of proteins and polymers?

1. Osmotic pressure

2. Lowering of vapour pressure 

3. Lowering of freezing point

4. Elevation in boiling point

Subtopic:  Osmosis & Osmotic Pressure |
 85%
Level 1: 80%+
AIPMT - 2000
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A solution contains a non-volatile solute of molecular mass M2. The molecular mass of solute in terms of osmotic pressure is:
where:

m2 → Mass of solute

V → Volume of solution

\(\pi\) → Osmotic pressure

1. M2=(m2π)VRT

2. M2=(m2V)RTπ

3. M2=(m2V)πRT

4. M2=(m2V)πRT

Subtopic:  Osmosis & Osmotic Pressure |
 82%
Level 1: 80%+
AIPMT - 2002
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The ideal solution indicates:

1. A – B attraction force is greater than A – A and B – B.
2. A – B attraction force is less than A – A and B – B.
3. Attraction force remains the same in A – A and B – B.
4. The volume of the solution is different from the sum of the volume of the solute and solvent.
Subtopic:  Raoult's Law |
 87%
Level 1: 80%+
AIPMT - 2002
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Beans get cooked earlier in a pressure cooker, because:

1. The boiling point increases with increasing pressure
2. The boiling point decreases with increasing pressure
3. The extra pressure of the pressure cooker softens the beans
4. Internal energy is not lost while cooking in a pressure cooker
Subtopic:  Introduction & Colligative properties |
 55%
Level 3: 35%-60%
AIPMT - 2001
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What is the mass percentage of carbon when 22 g of
benzene is dissolved in 122 g of carbon tetrachloride?

1. 89.72%

2. 33.72%

3. 20.72%

4. 63.572%

Subtopic:  Introduction & Colligative properties |
 65%
Level 2: 60%+
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The partial pressure of ethane over a solution containing 6.56 × 10–2 g of ethane is 1 bar. If the solution contains 5.00 × 10–2 g of ethane, the partial pressure of the gas will be:

1. 0.66 bar

2. 0.96 bar

3. 0.76 bar

4. 0.19 bar

Subtopic:  Concentration Terms & Henry's Law |
 73%
Level 2: 60%+
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The positive deviations from Raoult’s law mean the vapour pressure is:

1. Higher than expected.
2. Lower than expected.
3. As expected.
4. None of the above

Subtopic:  Raoult's Law |
 86%
Level 1: 80%+
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The vapour pressure of 1 molal solution of a non-volatile solute in water at 300 K would be:

(The vapour pressure of water at 300 K = 12.3 kPa)

1. 21.08 kPa 2. 12.08 kPa
3. 33.08 kPa 4. 4.08 kPa
Subtopic:  Relative Lowering of Vapour Pressure |
 77%
Level 2: 60%+
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A solution containing 30 g of non-volatile solute in 90 g of water has a vapour pressure of 2.8 kPa at 298 K. Further, 18 g of water is then added to the solution and the new vapour pressure becomes 2.9 kPa at 298 K.

The molar mass of the solute will be :

1.  23 g mol−1

2.  34 g mol−1

3.  15 g mol−1

4.  46 g mol−1

Subtopic:  Relative Lowering of Vapour Pressure |
Level 3: 35%-60%
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