The ideal solution indicates:

1.	A – B attraction force is greater than A – A and B – B.
2.	A – B attraction force is less than A – A and B – B.
3.	Attraction force remains the same in A – A and B – B.
4.	The volume of the solution is different from the sum of the volume of the solute and solvent.

Beans get cooked earlier in a pressure cooker, because:

What is the mass percentage of carbon when 22 g of
benzene is dissolved in 122 g of carbon tetrachloride?

1. 89.72%

2. 33.72%

3. 20.72%

4. 63.572%

The partial pressure of ethane over a solution containing 6.56 × 10^–2 g of ethane is 1 bar. If the solution contains 5.00 × 10^–2 g of ethane, the partial pressure of the gas will be:

1. 0.66 bar

2. 0.96 bar

3. 0.76 bar

4. 0.19 bar

The positive deviations from Raoult’s law mean the vapour pressure is:

1. Higher than expected.
2. Lower than expected.
3. As expected.
4. None of the above

The vapour pressure of 1 molal solution of a non-volatile solute in water at 300 K would be:

(The vapour pressure of water at 300 K = 12.3 kPa)

A solution containing 30 g of non-volatile solute in 90 g of water has a vapour pressure of 2.8 kPa at 298 K. Further, 18 g of water is then added to the solution and the new vapour pressure becomes 2.9 kPa at 298 K.

The molar mass of the solute will be :

1.  23 g mol⁻¹

2.  34 g mol⁻¹

3.  15 g mol⁻¹

4.  46 g mol⁻¹

Two elements A and B form compounds having formula AB₂ and AB₄. When dissolved in 20 g of benzene (C₆H₆), 1 g of AB₂ lowers the freezing point by 2.3 K whereas 1.0 g of AB₄ lowers it by 1.3 K. The atomic masses of A and B are respectively:

(K_f for benzene is 5.1 K kg mol^-1)

1. 15.59 u and 52.64 u

2. 25.59 u and 42.64 u

3. 13.59 u and 52.64 u

4. 23.59 u and 32.64 u

The type of inter-molecular interactions present in:

The insoluble compound in water is /are:

1. Phenol

2. Formic acid and toluene

3. Phenol and toluene 

4. Toluene and chloroform