The reaction of propanamide with ethanolic sodium hydroxide and bromine will give:

1.	Ethylamine	2.	Methylamine
3.	Propylamine	4.	Aniline

A compound "A", when reacted with PCl₅ and then with ammonia, gives "B". "B" on treatment with bromine and caustic potash produces "C". "C" on treatment with NaNO₂ and HCl at C and then boiling produces ortho-cresol. Compound "A" is:

1. o-Toluic acid

2. o-Chlorotoluene

3. o-Bromotoluene

4. m-Toluic acid

An organic compound ($C_3{H}_{9}N$) (A), when treated with nitrous acid, gave an alcohol, and N₂ gas was evolved. (A) on warming with CHCl₃ and caustic potash gave (C) which on reduction gave isopropylmethylamine. The structure of (A) is:

1.		2.
3.		4.

Which of the following compounds is most basic?

1.		2.
3.		4.

D is N-methyl aniline in the given below sequence of reaction:
\(\text A\xrightarrow{\bf\text{ reduction }}\text B\xrightarrow{\bf\text {CHCl}_3\text{/KOH}}\text C\xrightarrow{\bf\text{ reduction }}\text D\)

Structure of A can be:

1.		2.
3.	\(\mathrm{CH_3NH_2 }\)	4.

The products formed when Aniline reacts with $B{r}_2$ water, and $NaN{O}_2/HCl$ will be, respectively:

Aniline when diazotized in cold and then treated with dimethyl aniline gives a coloured product. Its structure would be:

1.
2.
3.
4.

Which chemical reaction leads to the formation of isocyanide?

1. Reimer Tiemann reaction.
2. Carbylamine reaction.
3. Hoffmann bromamide reaction.
4. None of the above.

The final product C, obtained in this reaction, would be:

1.		2.
3.		4.

An aromatic compound ‘A’ on treatment with ammonia and heating forms compound ‘B’ which on heating with Br₂ and KOH forms a compound ‘C’ of molecular formula C₆H₇N. The Substrate 'A' is:

1. Aniline

2. Benzoic acid 

3. Benzamide

4. Benzamine