D is N-methyl aniline in the given below sequence of reaction:
\(\text A\xrightarrow{\bf\text{ reduction }}\text B\xrightarrow{\bf\text {CHCl}_3\text{/KOH}}\text C\xrightarrow{\bf\text{ reduction }}\text D\)

Structure of A can be:

1.		2.
3.	\(\mathrm{CH_3NH_2 }\)	4.

The products formed when Aniline reacts with $B{r}_2$ water, and $NaN{O}_2/HCl$ will be, respectively:

Aniline when diazotized in cold and then treated with dimethyl aniline gives a coloured product. Its structure would be:

1.
2.
3.
4.

Which chemical reaction leads to the formation of isocyanide?

1. Reimer Tiemann reaction.
2. Carbylamine reaction.
3. Hoffmann bromamide reaction.
4. None of the above.

The final product C, obtained in this reaction, would be:

1.		2.
3.		4.

A method for the identification of primary, secondary and tertiary amines is:

1. Azo-dye test

2. Carbylamine test

3. Hinsberg’s test

4. None of these

Aromatic primary amines cannot be prepared by Gabriel phthalimide synthesis because :

${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{N}}_2\mathrm{Cl}+{\mathrm{H}}_3{\mathrm{PO}}_2+{\mathrm{H}}_2\mathrm{O}$:

The product from the above reaction would be -

$1.{\mathrm{C}}_6{\mathrm{H}}_5\mathrm{NC}$

$2.<mspace\; width="1em"></mspace>{\mathrm{C}}_6{\mathrm{H}}_6{\mathrm{CH}}_3$

$3.{\mathrm{C}}_6{\mathrm{H}}_5\mathrm{CN}$

$4.<mspace\; width="1em"></mspace>{\mathrm{C}}_6{\mathrm{H}}_6$

The primary amine is -

1. ${\left({\mathrm{CH}}_3\right)}_2{\mathrm{CHNH}}_2$

2. ${{\mathrm{CH}}_3\left({\mathrm{CH}}_2\right)}_2\mathrm{NH}-{\mathrm{CH}}_3$

3. ${{\mathrm{CH}}_3\left({\mathrm{CH}}_2\right)}_2\mathrm{N}{\left({\mathrm{CH}}_3\right)}_2$

4. None of the above

Which of the following is a secondary amine is -

$1.<mspace\; width="1em"></mspace>{\mathrm{CH}}_3{\left({\mathrm{CH}}_2\right)}_2{\mathrm{NH}}_2<mspace\; width="1em"></mspace>$
$2.<mspace\; width="1em"></mspace>{\left({\mathrm{CH}}_3{\mathrm{CH}}_2\right)}_2{\mathrm{NCH}}_3<mspace\; width="1em"></mspace>$
$3.<mspace\; width="1em"></mspace>{\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{NHCH}}_3$
$4.<mspace\; width="1em"></mspace>{\left({\mathrm{CH}}_3\right)}_3{\mathrm{NH}}_2$