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#5 | Field due to Short Bar Magnet

(Physics) > Magnetism and Matter

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Related Practice Questions :

A bar magnet of length l and magnetic dipole moment M is bent to form an arc which subtends an angle of $120\xb0$ at centre. The new magnetic dipole moment will be

1. $\frac{3\mathrm{M}}{2\mathrm{\pi}}$

2. $\frac{3\sqrt{3}\mathrm{M}}{2\mathrm{\pi}}$

3. $\frac{3\mathrm{M}}{\mathrm{\pi}}$

4. $\frac{2\mathrm{M}}{\mathrm{\pi}}$

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The unit of pole strength is

(1) $A{m}^{2}$

(2) Am

(3) $\frac{{A}^{2}}{m}$

(4) $\frac{{A}^{2}}{{m}^{2}}$

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The magnetic field at a point x on the axis of a small bar magnet is equal to the field at a point y on the equator of the same magnet. The ratio of the distances of x and y from the centre of the magnet is

(a) ${2}^{-3}$

(b) ${2}^{\raisebox{1ex}{$-1$}\!\left/ \!\raisebox{-1ex}{$3$}\right.}$

(c) ${2}^{3}$

(d) ${2}^{\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$3$}\right.}$

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Points A and B are situated perpendicular to the axis of a 2cm long bar magnet at large distances X and 3X from its centre on opposite sides. The ratio of the magnetic fields at A and B will be approximately equal to

(a) 1 : 9 (b) 2 : 9

(c) 27 : 1 (d) 9 : 1

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Two short magnets with their axes horizontal to the magnetic meridian are placed with their centres 40 *cm *east and 50 *cm* west of the magnetic needle. If the needle remains undeflected, the ratio of their magnetic moments is

(a) 4:5

(b) 16:25

(c) 64:125

(D) 2:$\sqrt{5}$

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