#5 | Bulk Modules & Shear Modules
(Physics) > Mechanical Properties of Solids
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Related Practice Questions :

The elastic energy stored in a wire of Young's Modulus Y is -

1. Y×strain2volume

2. stress×strain×volume

3. strain2×volume2Y

4. 12×stress×strain×volume

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The bulk modulus of a spherical object is B. If it is subjected to uniform pressure p, the fractional decrease in radius is 

(a)PB

(b) B3p

(c) 3pB

(d)p3B

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The Young's modulus of steel is twice that of brass. Two wires of same length and of same area of cross-section, one of steel and another of brass are suspended from the same roof. If we want the lower ends of the wires to be at the same level, then the weight added to the steel and brass wires must be in the ratio of

(a)1:2

(b)2:1

(c)4:1

(d)1:1

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The Young's modulus of a wire of length L and radius r is Y N/m2. If the length and radius are reduced to L/2 and r/2, then its Young's modulus will be -

(a) 1:1                           (b) 1:4

(c) 1:8                             (d) 8:1

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A force F is needed to break a copper wire having radius R. The force needed to break a copper wire of radius 2R will be

(a) F/2                                      (b) 2F 

(c) 4F                                       (d) F/4

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