#29 | Entropy Change Calculation: Case II, III & IV
(Chemistry) > Thermodynamics
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Change in enthalpy for reaction,

2H2O2(l) 2H2O(l) + O2(g)

if the heat of formation of H2O2(l) and H2O(l) are -188 and -286 kJ/mol respectively is           

(a) -196 kJ/mol              (b) + 196 kJ/mol

(c) +948 kJ/mol             (d) -948 kJ/mol

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If 50 calorie are added to a system and system does work of 30 calorie on surroundings, the change in internal energy of system is:

(a) 20 cal                             (b) 50 cal

(c) 40 cal                             (d) 30 cal

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Which statements are correct?

(a) 2.303 logP2P1=Hvap.RT2-T1T1T2 is called Clausius-Clapeyron equation

(b) Hvap.Boiling Point=88 J mol-1K-1 is called Trouton's rule

(c) Entropy is a measure of unavailable energy, i.e.,

     unavailable energy = entropy x temperature

(d) All of the above

 

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Consider the reaction

N2(g) + 3H2(g)2NH3(g) carried out at constant temperature and pressure. If H and E are enthalpy change and internal energy change respectively, which of the following expression is True?

1.  HE                        2. H=E3.  H<E                        4. H>E

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What will be the standard enthalpy of reaction for the following reaction using the listed enthalpies of reaction:-

3Co(s) + 2O2(g)Co3O4(s);       H=?

2Co(s) + O2(g) 2CoO(s)          H1= -475.8 KJ

6CoO(s) + O2(g) 2Co3O4(s)     H2 = -355.0 KJ

(1) -891.2 KJ

(2) -120.8 KJ

(3) 891.2 KJ

(4) -830.8 KJ

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