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#3 | Kepler's 3rd Law

(Physics) > Gravitation

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The distance of neptune and saturn from sun are nearly ${10}^{13}$ and ${10}^{12}$ meters respectively. Assuming that they move in circular orbits, their periodic times will be in the ratio

(a) $\sqrt{10}$ (b) 100

(c) $10\sqrt{10}$ (d) $1/\sqrt{10}$

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The figure shows the motion of a planet around the sun in an elliptical orbit with sun at the focus. The shaded areas A and B are also shown in the figure which can be assumed to be equal. If ${t}_{1}$ and ${t}_{2}$ represent the time for the planet to move from *a* to *b* and *d* to *c* respectively, then

(a) ${t}_{1}<{t}_{2}$

(b) ${t}_{1}>{t}_{2}$

(c) ${t}_{1}={t}_{2}$

(d) ${t}_{1}\le {t}_{2}$

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The period of a satellite in a circular orbit of radius *R* is *T*, the period of another satellite in a circular orbit of radius 4*R* is

(a)4T (b)$\frac{T}{4}$

(c)8T (d)$\frac{T}{8}$

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