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#48-Relative motion-3

(Physics) > Motion in A Straight Line

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Related Practice Questions :

Two men P & Q are standing at corners A & B of square ABCD of side 8 m. They start moving along the track with constant speed 2 m/s and 10 m/s respectively. The time when they will meet for the first time, is equal to:

(1) 2 sec

(2) 3 sec

(3) 1 sec

(4) 6 sec

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Two cars *A* and *B* are travelling in the same direction with velocities *v*_{1} and *v*_{2} $({v}_{1}>{v}_{2})$. When the car *A* is at a distance *d* behind car *B*, the driver of the car *A* applied the brake producing a uniform retardation *a.* There will be no collision when

1. $d<\frac{{({v}_{1}-{v}_{2})}^{2}}{2a}$

2. $d<\frac{{v}_{1}^{2}-{v}_{2}^{2}}{2a}$

3. $d>\frac{{({v}_{1}-{v}_{2})}^{2}}{2a}$

4. $d>\frac{{v}_{1}^{2}-{v}_{2}^{2}}{2a}$

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A student is standing at a distance of 50 metres from the bus. As soon as the bus begins its motion with an acceleration of 1*ms*^{–2}, the student starts running towards the bus with a uniform velocity *u*. Assuming the motion to be along a straight road, the minimum value of *u*, so that the student is able to catch the bus is

1. 5 *ms*^{–1}

2. 8 *ms*^{–1}

3. 10 *ms*^{–1}

4. 12 *ms*^{–1}

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A man is 45 *m* behind the bus when the bus starts accelerating from rest with acceleration of 2.5 *m/s*^{2}. With what minimum velocity should the man start running to catch the bus?** **

1. 12 *m/s*

2. 14 *m/s*

3. 15 *m/s*

4. 16 *m/s*

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Two trains, each 50 *m* long are travelling in opposite direction with velocity 10 *m/s *and 15 *m/s*. The time of crossing is

(1) 10 s

(2) 4 *s*

(3) $2\sqrt{3}s$

(4) $4\sqrt{3}s$

PMT - 1999

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