#37 | Differential Form of First Law
(Physics) > Thermodynamics
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A system is taken from state A to state B along two different paths 1 and 2. If the heat absorbed and work done by the system along these two paths are Q1, Q2 and W1, W2 respectively, then

(1) Q1=Q2

(2) W1=W2

(3) Q1-W1=Q2-W2

(4) Q1+W1=Q2+W2

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Figure below shows two paths that may be taken by a gas to go from a state A to a state C. In process AB, 400 J of heat is added to the system and in process BC, 100 J of heat is added to the system. The heat absorbed by the system in the process AC will be-


(a) 380 J 
(b) 500 J
(c) 460 J
(d) 300 J

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A thermodynamic system is taken through the cycle ABCD as shown in figure. Heat rejected by the gas during the cycle is 

(a)2 pV                                     (b)4 pV

(c)12pV                                    (d)pV

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An ideal gas goes from state A to state B

via three different processes as indicated 

in the p-V diagram

If Q1, Q2, Q3 indicates the heat absorbed

by the gas along the three processes and 

U1, U2, U3 indicates the change in 

internal energy along the three processes

respectively, then

(a) Q1>Q2>Q3 and U1= U2= U3

(b) Q3>Q2>Q1 and U1= U2= U3

(c) Q1=Q2=Q3 and U1>U2>U3

(d) Q3>Q2>Q1 and U1>U2>U3

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The internal energy change in a system that has absorbed 2 kcal of heat and done 500 J of work is 

(a) 8900 J                                      (b) 6400 J

(c) 5400 J                                      (d) 7900 J

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