If the mean free path of atoms is doubled then the pressure of the gas will become:
1. \(P/4\)
2. \(P/2\)
3. \(P/8\)
4. \(P\)
The mean free path of molecules of a gas, (radius r) is inversely proportional to :
1. r3
2. r2
3. r
4. \(\sqrt{r}\)
If the pressure in a closed vessel is reduced by drawing out some gas, the mean free path of the molecules:
| 1. | decreases |
| 2. | increases |
| 3. | remains unchanged |
| 4. | increases or decreases according to the nature of the gas |
Assertion: At a particular temperature, the value of the mean free path increases with a decrease in pressure.
Reason: All the gas molecules at a particular temperature possess the same speed.
- If both the assertion and the reason are true and the reason is a correct explanation of the assertion
- If both the assertion and reason are true but the reason is not a correct explanation of the assertion
- If the assertion is true but the reason is false
- If both the assertion and reason are false
When the gas in an open container is heated, the mean free path:
1. Increases
2. Decreases
3. Remains the same
4. Any of the above depending on the molar mass
A closed container having an ideal gas is heated gradually to increase the temperature by 20% The mean free path will become/remain:
1. 20% more
2. Same
3. 20% less
4. 33% less
| 1. | \(3:1\) | 2. | \(9:1\) |
| 3. | \(1:1\) | 4. | \(1:4\) |
The mean free path for a gas, with molecular diameter \(d\) and number density \(n,\) can be expressed as:
| 1. | \( \dfrac{1}{\sqrt{2} n \pi {d}^2} \) | 2. | \( \dfrac{1}{\sqrt{2} n^2 \pi {d}^2} \) |
| 3. | \(\dfrac{1}{\sqrt{2} n^2 \pi^2 d^2} \) | 4. | \( \dfrac{1}{\sqrt{2} n \pi {d}}\) |
On increasing number density for a gas in a vessel, the mean free path of a gas:
(1) Decreases
(2) Increases
(3) Remains same
(4) Becomes double
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