If the mass of a bob in a simple pendulum is increased to thrice its original mass and its length is made half its original length, then the new time period of oscillation is \( \dfrac{x}{2}\) times its original time period. The value of \(x\) is:
1. \(\sqrt2\) 2. \(2\sqrt3\)
3. \(4\) 4. \(\sqrt3\)
Subtopic:  Angular SHM |
 69%
From NCERT
NEET - 2024
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The period of oscillation of a simple pendulum of length \(L\) suspended from the roof of a vehicle which moves without friction down an inclined plane of inclination \(\theta\), is given by:
1. \(2\pi\sqrt{\frac{L}{g\cos\theta}}\)
2. \(2\pi\sqrt{\frac{L}{g\sin\theta}}\)
3. \(2\pi\sqrt{\frac{L}{g}}\)
4. \(2\pi\sqrt{\frac{L}{g\tan\theta}}\)

Subtopic:  Angular SHM |
 60%
From NCERT
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Two spherical bobs of masses \(M_A\) and \(M_B\) are hung vertically from two strings of length \(l_A\) and \(l_B\) respectively. If they are executing SHM with frequency as per the relation \(f_A=2f_B,\) Then:
1. \(l_A = \frac{l_B}{4}\)
2. \(l_A= 4l_B\)
3. \(l_A= 2l_B~\&~M_A=2M_B\)
4. \(l_A= \frac{l_B}{2}~\&~M_A=\frac{M_B}{2}\)

Subtopic:  Angular SHM |
 75%
From NCERT
AIPMT - 2000
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A simple pendulum oscillating in air has a period of \(\sqrt3\) s. If it is completely immersed in non-viscous liquid, having density \(\left(\dfrac14\right)^{\text{th}}\) of the material of the bob, the new period will be:
1. \(2\sqrt3\) s 2. \(\dfrac{2}{\sqrt3}\) s
3. \(2\) s 4. \(\dfrac{\sqrt 3}{2}\) s
Subtopic:  Angular SHM |
 53%
From NCERT
NEET - 2023
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The time period of a simple pendulum in a stationary lift is \(T.\) If the lift accelerates upward with an acceleration of \(\dfrac g 6\) (where \(g\) is the acceleration due to gravity), then the time period of the pendulum would be:
1. \(\sqrt{\dfrac{6}{5}} ~T \) 2. \(\sqrt{\dfrac{5}{6}} ~T\)
3. \(\sqrt{\dfrac{6}{7}}~T\) 4. \(\sqrt{\dfrac{7}{6}} ~T\)
Subtopic:  Angular SHM |
 79%
From NCERT
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If a simple pendulum is brought deep inside a mine from the earth's surface, its time period of oscillation will:

1. increase
2. decrease 
3. remain the same
4. be any of the above, depending on the length of the pendulum

Subtopic:  Angular SHM |
 68%
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If a simple pendulum be suspended in an elevator which is moving upward, its time period is found to decrease by \(2\%.\) The acceleration of the elevator is (in magnitude):
1. \(2\%\) of \(g\)
2. \(1\%\) of \(g\)
3. \(4\%\) of \(g\)
4. \(102\%\) of \(g\)
Subtopic:  Angular SHM |
 77%
From NCERT
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