- 1(current)
Q. No.Two batteries, one of emf \(18~\text{V}\) and internal resistance \(2~\Omega\) and the other of emf \(12~\text V\) and internal resistance \(1~\Omega,\) are connected as shown. Reading of the voltmeter is:
(if a voltmeter is ideal)
1. \(14~\text V\)
2. \(15~\text V\)
3. \(18~\text V\)
4. \(30~\text V\)
Subtopic: Â Grouping of Cells |
 77%
Level 2: 60%+
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Two hundred cells of the same emf \(E\) and same internal resistance \(r\) are connected in series in the same order without external resistance. The potential drop across \(50\) cells is found to be:
1. \(50E\)
2. \(150E\)
3. \(200E\)
4. zero
1. \(50E\)
2. \(150E\)
3. \(200E\)
4. zero
Subtopic: Â Grouping of Cells |
Level 3: 35%-60%
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A battery consists of a variable number \(n\) of identical cells (having internal resistance \(r\) each) which are connected in series. The terminals of the battery are short-circuited and the current \(I\) is measured. Which of the graphs shows the correct relationship between \(I\) and \(n?\)
| 1. |  |
2. |  |
| 3. |  |
4. |  |
Subtopic: Â Grouping of Cells |
 67%
Level 2: 60%+
NEET - 2018
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Two cells having emfs \(3\) V and \(2\) V are connected in parallel and they give an emf of \(0.5\) V in the same sense as \(3\) V \(-\) cell. The internal resistances of the cells are \(r_1\) and \(r_2\) respectively. If one cell is reversed, their combined emf becomes \(2.5\) V. The ratio of their internal resistances \(\Big(\dfrac{r_1}{r_2}\Big) \) is:
1. \(1\)
2. \(\dfrac12\)
3. \(\dfrac21\)
4. \(\sqrt2\)
1. \(1\)
2. \(\dfrac12\)
3. \(\dfrac21\)
4. \(\sqrt2\)
Subtopic: Â Grouping of Cells |
 67%
Level 2: 60%+
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