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The potential at a point P due to a charge of 4 × 10^{–7 }C located 9 cm away is:

$1.3\times {10}^{6}V$

$2.4\times {10}^{6}V$

$3.3\times {10}^{4}V$

$4.4\times {10}^{4}V$

Subtopic: Electric Potential |

78%

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The potential at point P is $4\times {10}^{4}V$. The work done in bringing a charge of 2 × 10^{–9 }C from infinity to the point P is:

$1.6\times {10}^{-6}J$

$2.4\times {10}^{-4}J$

$3.8\times {10}^{-5}J$

$4.9\times {10}^{-4}J$

Subtopic: Electric Potential |

85%

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Two charges 3 × 10^{–8} C and –2 × 10^{–8} C are located 15 cm apart. At what point on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.

1. 9 cm away from 3 × 10^{–8} C

2. 25 cm away from 3 × 10^{–8} C

3. 45 cm away from 3 × 10^{–8} C

4. Both (1) and (3)

Subtopic: Electric Potential |

52%

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Figures (a) and (b) show the field lines of a positive and negative point charge respectively.

The signs of the potential difference ${V}_{P}-{V}_{Q}\mathrm{and}{V}_{B}-{V}_{A}\mathrm{are}\mathrm{respectively}:$

$1.+,-$

$2.+,+$

$3.-,+$

$4.-,-$

Subtopic: Electric Potential |

61%

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Figures (a) and (b) show the field lines of a positive and negative point charge respectively. The signs of the potential energy difference of a small negative charge between the points Q and P & A and B are respectively:

$1.+,-$

$2.+,+$

$3.-,+$

$4.-,-$

Subtopic: Electric Potential Energy |

53%

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Figures (a) and (b) show the field lines of a positive and negative point charge respectively. The sign of the work done by the field in moving a small positive charge from Q to P and the sign of the work done by the external agency in moving a small negative charge from B to A, respectively, will be:

$1.+,-$

$2.+,+$

$3.-,+$

$4.-,-$

Subtopic: Electric Potential Energy |

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Figures (a) and (b) show the field lines of a positive and negative point charge respectively. The kinetic energy of a small negative charge in going from B to A:

1. decreases.

2. increases.

3. remains the same.

4. first increases and then decreases.

Subtopic: Electric Potential Energy |

58%

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Four charges are arranged at the corners of a square ABCD of side d, as shown in the figure. The work required to put together this arrangement will be:

$1.\frac{-{q}^{2}}{4\pi {\epsilon}_{0}d}\left(4-\sqrt{2}\right)$

$2.\frac{-{q}^{2}}{4\pi {\epsilon}_{0}d}\left(2-\sqrt{2}\right)$

$3.\frac{-{q}^{2}}{4\pi {\epsilon}_{0}d}\left(4+\sqrt{2}\right)$

$4.\frac{-{q}^{2}}{4\pi {\epsilon}_{0}d}\left(2+\sqrt{2}\right)$

Subtopic: Electric Potential Energy |

57%

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Four charges are arranged at the corners of a square ABCD of side d, as shown in the figure. A charge ${q}_{0}$ is brought from $\infty $ to the centre E of the square, the four charges being held fixed at its corners. How much work is needed to do this?

$1.\frac{-{\mathrm{q}}^{2}}{4{\mathrm{\pi \epsilon}}_{0}\mathrm{d}}\left(4-\sqrt{2}\right)$

$2.\mathrm{zero}$

$3.\frac{-{\mathrm{q}}^{2}}{4{\mathrm{\pi \epsilon}}_{0}\mathrm{d}}\left(4+\sqrt{2}\right)$

$4.\frac{-{\mathrm{q}}^{2}}{4{\mathrm{\pi \epsilon}}_{0}\mathrm{d}}\left(2+\sqrt{2}\right)$

Subtopic: Electric Potential Energy |

65%

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The electrostatic potential energy of a system consisting of two charges 7 µC and –2 µC (and with no external field) placed at (–9 cm, 0, 0) and (9 cm, 0, 0) respectively is:

1. 0.2 J

2. -0.7 J

3. -0.2 J

4. 0.7 J

Subtopic: Electric Potential Energy |

78%

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