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The electrostatic force between the metal plates of an isolated parallel plate capacitor \(C\) having a charge \(Q\) and area \(A\) is:

1. | independent of the distance between the plates. |

2. | linearly proportional to the distance between the plates. |

3. | proportional to the square root of the distance between the plates. |

4. | inversely proportional to the distance between the plates. |

Subtopic: Â Capacitance |

Â 61%

From NCERT

NEET - 2018

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The diagrams below show regions of equipotentials.

A positive charge is moved from \(\mathrm A\) to \(\mathrm B\) in each diagram. Then:

1. | the maximum work is required to move \(q\) in figure(iii). |

2. | in all four cases, the work done is the same. |

3. | the minimum work is required to move \(q\) in the figure(i). |

4. | the maximum work is required to move \(q\) in figure(ii). |

Subtopic: Â Equipotential Surfaces |

Â 90%

From NCERT

NEET - 2017

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A capacitor is charged by a battery. The battery is removed and another identical uncharged capacitor is connected in parallel. The total electrostatic energy of the resulting system:

1. | \(2\) | decreases by a factor of

2. | remains the same |

3. | \(2\) | increases by a factor of

4. | \(4\) | increases by a factor of

Subtopic: Â Energy stored in Capacitor |

Â 58%

From NCERT

NEET - 2017

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An electric dipole is place at an angle of \(30^{\circ}\) with an electric field intensity \(2\times10^{5}~\text{N/C}\). It experiences a torque equal to \(4~\text{Nm}\). The charge on the dipole, if the dipole length is \(2~\text{cm}\), is:

1. | \(8~\text{mC}\) | 2. | \(2~\text{mC}\) |

3. | \(5~\text{mC}\) | 4. | \(7~\mu\text{C}\) |

Subtopic: Â Energy of Dipole in an External Field |

Â 86%

From NCERT

NEET - 2016

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A parallel-plate capacitor of area A, plate separation d, and capacitance C is filled with four dielectric materials having dielectric constants ${k}_{1},{k}_{2},{k}_{3}$ $$and ${k}_{4}$ as shown in the figure below. If a single dielectric material is to be used to have the same capacitance C in this capacitor, then its dielectric constant k is given by

(a) $\mathrm{k}={\mathrm{k}}_{1}+{\mathrm{k}}_{2}+{\mathrm{k}}_{3}+3{\mathrm{k}}_{4}$

(b) $k=\frac{2}{3}\left({k}_{1}+{k}_{2}+{k}_{3}\right)+2{k}_{4}$

(c) $\frac{1}{k}=\frac{3}{2\left({k}_{1}+{k}_{2}+{k}_{3}\right)}+\frac{1}{2{k}_{4}}$

(d) $\frac{1}{\mathrm{k}}=\frac{1}{{\mathrm{k}}_{1}}+\frac{1}{{\mathrm{k}}_{2}}+\frac{1}{{\mathrm{k}}_{3}}+\frac{3}{2{\mathrm{k}}_{4}}$

Subtopic: Â Dielectrics in Capacitors |

Â 68%

From NCERT

NEET - 2016

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A capacitor of \(2~\mu\text{F}\) is charged as shown in the figure. When the switch \({S}\) is turned to position \(2,\), the percentage of its stored energy dissipated is:

1. \(20\%\)

2. \(75\%\)

3. \(80\%\)

4. \(0\%\)

2. \(75\%\)

3. \(80\%\)

4. \(0\%\)

Subtopic: Â Energy stored in Capacitor |

Â 71%

From NCERT

NEET - 2016

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