Select Chapter Topics:
Q. No.A circular loop of radius \(\mathrm{R}\), enters a region of uniform magnetic field \(\mathrm{B}\) as shown in the diagram. The field \((\mathrm{B})\) is perpendicular to the plane of the loop while the velocity of the loop,\(\mathrm{v}\), is along its plane. The induced EMF:
1.
increases continuously.
2.
decreases continuously.
3.
first increases and then decreases.
4.
remains constant throughout.
Subtopic: Faraday's Law & Lenz Law |
70%
From NCERT
Please attempt this question first.
Hints
Please attempt this question first.
A triangular wire frame, in the form of an equilateral triangle PQR moves with a uniform velocity into a region where there is a uniform magnetic field \(B\). The edge PQ is parallel to the boundary of the region and the velocity \(v\) is perpendicular to it. The emf(\(E\)) induced within the frame is plotted as a function of time \(t,\) starting from when the frame enters the magnetic field. \(E\) is given by:
1. \(Bv^2t\)
2. \(2Bv^2t\)
3. \(\frac{\sqrt3}{2}Bv^2t\)
4. \(\frac{2}{\sqrt3}Bv^2t\)
1. \(Bv^2t\)
2. \(2Bv^2t\)
3. \(\frac{\sqrt3}{2}Bv^2t\)
4. \(\frac{2}{\sqrt3}Bv^2t\)
Subtopic: Motional emf |
From NCERT
Please attempt this question first.
Hints
Please attempt this question first.
A small solenoid is kept inside a much larger solenoid, with their axes parallel to each other. The small solenoid has a cross-sectional radius \(r_1,\) length \(l_1\) and the total number of turns \(N_1.\) The corresponding quantities for the larger solenoid are: \(r_2,~ l_2,~ N_2\) respectively.
Their mutual inductance is (nearly) given by:
1. \(\frac{\mu_0\pi r^2_1N_1N_2}{l_2}\)
2. \(\frac{\mu_0\pi r^2_1N_1N_2}{\sqrt{l_1l_2}}\)
3. \(\frac{\mu_0\pi r^2_1N_1N_2}{l_1}\)
4. \(\frac{\mu_0~\pi r_1r_2N_1N_2}{\sqrt{l_1}}\)
Their mutual inductance is (nearly) given by:
1. \(\frac{\mu_0\pi r^2_1N_1N_2}{l_2}\)
2. \(\frac{\mu_0\pi r^2_1N_1N_2}{\sqrt{l_1l_2}}\)
3. \(\frac{\mu_0\pi r^2_1N_1N_2}{l_1}\)
4. \(\frac{\mu_0~\pi r_1r_2N_1N_2}{\sqrt{l_1}}\)
Subtopic: Mutual Inductance |
61%
From NCERT
Please attempt this question first.
Hints
Please attempt this question first.
A straight horizontal wire of mass \(m\) and length \(l,\) and having a negligible resistance can slide freely on a pair of conducting parallel rails, placed vertically. The rails are connected at the top by a capacitor \(C.\) A uniform magnetic field \(B\) exists in the region, perpendicular to the plane of the rails. The wire:
| 1. | falls with uniform velocity. |
| 2. | accelerates down with acceleration less than \(g\). |
| 3. | accelerates down with acceleration equal to \(g\). |
| 4. | moves down and eventually comes to rest. |
Subtopic: Motional emf |
68%
From NCERT
Please attempt this question first.
Hints
Please attempt this question first.
A rectangular loop of conducting wire is bent symmetrically so that its two plane halves are inclined at right angles with respect to each other (i.e. \(\angle \text { PQR }=\angle S T U=90^{\circ}\)). Every segment has a length 'a' (PQ = QR = RS = ... = UP = a). A uniform time-dependent magnetic field B(t) acts on the loop, making an angle '\(\alpha\)' with the lower half of the loop and '\(90^o - \alpha \)' with the upper half. The EMF induced in the loop is proportional to:
\(1.~ (\cos \alpha+\sin \alpha) \frac{d B}{d t}\\ 2.~ (\cos \alpha-\sin \alpha) \frac{d B}{d t}\\ 3.~ (\tan \alpha+\cot \alpha) \frac{d B}{d t}\\ 4.~ (\tan \alpha-\cot \alpha) \frac{dB}{d t}\)
\(1.~ (\cos \alpha+\sin \alpha) \frac{d B}{d t}\\ 2.~ (\cos \alpha-\sin \alpha) \frac{d B}{d t}\\ 3.~ (\tan \alpha+\cot \alpha) \frac{d B}{d t}\\ 4.~ (\tan \alpha-\cot \alpha) \frac{dB}{d t}\)
Subtopic: Faraday's Law & Lenz Law |
From NCERT
Please attempt this question first.
Hints
Please attempt this question first.
The self-inductance of a long solenoid of cross-section \(A,\) total length \(L\) and total number of turns \(N,\) is (approximately):
1. \(\frac{\mu_0A}{L}\cdot N\)
2. \(\frac{\mu_0A}{L}\cdot N^2\)
3. \(\frac{\mu_0L^3}{A}\cdot N\)
4. \(\frac{\mu_0L^3}{A}\cdot N^2\)
1. \(\frac{\mu_0A}{L}\cdot N\)
2. \(\frac{\mu_0A}{L}\cdot N^2\)
3. \(\frac{\mu_0L^3}{A}\cdot N\)
4. \(\frac{\mu_0L^3}{A}\cdot N^2\)
Subtopic: Self - Inductance |
79%
From NCERT
Please attempt this question first.
Hints
Please attempt this question first.
A conducting circular wire of radius \(r\) is moving with constant velocity \(v\) towards the right in a uniform magnetic field \(B.\) We consider two points \(X,Y\) such that chord \(XY\) is perpendicular to the velocity \(v\) and is at a distance \(x\) from the centre \((O)\) of the circle. The EMF induced between \(X,Y\) is \(\varepsilon.\) Then, \(\varepsilon\) is proportional to:
1. \(x\)
2. \(\sqrt{r^2-x^2}\)
3. \(r\)
4. \(x\sqrt{r^2-x^2}\)
1. \(x\)
2. \(\sqrt{r^2-x^2}\)
3. \(r\)
4. \(x\sqrt{r^2-x^2}\)
Subtopic: Motional emf |
74%
From NCERT
Please attempt this question first.
Hints
Please attempt this question first.
An \(L\)-shaped rod \((ABC;AB=BC=a)\) moves in its own plane with a velocity \(v\) parallel to \(AB.\) There is a uniform magnetic field \(B\) acting into the plane as shown. The emf developed between \(A,C\) is:
1. \(Bav\)
2. \(\sqrt2Bav\)
3. \(\frac{Bav}{2}\)
4. zero
1. \(Bav\)
2. \(\sqrt2Bav\)
3. \(\frac{Bav}{2}\)
4. zero
Subtopic: Motional emf |
54%
From NCERT
Please attempt this question first.
Hints
Please attempt this question first.
A square loop of side \(1\) m and resistance \(1\) \(\Omega\) is placed in a magnetic field of \(0.5\) T. If the plane of the loop is perpendicular to the direction of the magnetic field, the magnetic flux through the loop is:
| 1. | \(0\) | 2. | \(2\) weber |
| 3. | \(0.5\) weber | 4. | \(1\) weber |
Subtopic: Magnetic Flux |
66%
From NCERT
NEET - 2022
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh
Hints
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh
A big circular coil of \(1000\) turns and average radius \(10~\text{m}\) is rotating about its horizontal diameter at \(2~\text{rad s}^{-1}\). If the vertical component of earth's magnetic field at that place is \(2\times 10^{-5}~\text{T}\) and electrical resistance of the coil is \(12.56~\Omega,\) then the maximum induced current in the coil will be:
1. \(2~\text{A}\)
2. \(0.25~\text{A}\)
3. \(1.5~\text{A}\)
4. \(1~\text{A}\)
1. \(2~\text{A}\)
2. \(0.25~\text{A}\)
3. \(1.5~\text{A}\)
4. \(1~\text{A}\)
Subtopic: Faraday's Law & Lenz Law |
55%
From NCERT
NEET - 2022
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh
Hints
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh
Select Chapter Topics:
© 2024 GoodEd Technologies Pvt. Ltd.