# NEET Physics Electric Charges and Fields Questions Solved

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Initially if we see half bubble

So, in equilibrium,

$\left({\mathrm{P}}_{\mathrm{in}}\right)\mathrm{A}=\left({\mathrm{P}}_{\mathrm{out}}\right)\mathrm{A}+\left(4\mathrm{\pi r}\right)\mathrm{S}$

If we give charge to this bubble

If we consider only half bubble, net electric force is vertically downward

Since , bubble expands

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Using Gauss law-
Imagine a case when a point charge q is placed at the centre of a cube of side L.

 $⇒$ Flux passing through cube=$\mathrm{q}/{\in }_{0}$ $⇒$ By symmetry, flux passing through each square =$\mathrm{q}/6{\in }_{0}$

When the charge is placed closer to the square face i.e. at L/2, flux passing through square face will be more.
So:- $\frac{\mathrm{q}}{6{\in }_{0}}<\varnothing <\frac{\mathrm{q}}{{\in }_{0}}$

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