# NEET Physics Motion in A Straight Line Questions Solved

A ball is thrown upward with a certain speed. It passes through the same point at 3 second and 7 second from the start. The maximum height achieved by the ball is

1.  500 m

2.  250 m

3.  125 m

4.  450 m

(3)

As upward and downward motion are symmetric [Time taken from A$\to$B is same as time taken from B$\to$C]

So time to reach highest point is 5s. Same time is required to reach from B to ground.

Time to reach highest point after 3sec = $\frac{7-3}{2}=2sec.$

Time to reach highest point from ground = 3+2 = 5sec.

For downward motion,

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• 53%
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$a=\frac{dv}{dt}=\frac{dv}{ds}×\frac{ds}{dt}=v×\frac{dv}{ds}$

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(1)

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• 9%

(1)

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Distance travelled in t second,

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A point moves in a straight line under the retardation a${\mathrm{v}}^{2}$. If the initial velocity is u, the distance covered in 't' seconds is-

1.  $\mathrm{aut}$

2.

3.

4.

Difficulty Level:

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(2)

Upward journey                                                                   Downward journey

Net acceleration = -(a+g)                                          Net acceleration = g - a
-ve indicates retardation

Difficulty Level:

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