- 1(current)
Q. No.A straight current-carrying wire carrying current \(I\) passes perpendicular to the plane of an imaginary rectangular loop PQRS, passing through its centre O (into the diagram). The diagonals intersect at \(60^\circ,\) and side PS is smaller than side PQ. The value of \(\int \vec{B} \cdot \overrightarrow{dl}\) evaluated from P to Q (along PQ) has the magnitude:
\(1.~ \frac{\mu_{0} I}{6}\\ 2.~ \frac{2 \mu_{0} I}{6}\\ 3.~ \frac{4\mu_{0} I}{6}\\ 4.~\frac{5\mu_{0} I}{6}\)
\(1.~ \frac{\mu_{0} I}{6}\\ 2.~ \frac{2 \mu_{0} I}{6}\\ 3.~ \frac{4\mu_{0} I}{6}\\ 4.~\frac{5\mu_{0} I}{6}\)
Subtopic: Â Ampere Circuital Law |
From NCERT
Please attempt this question first.
Hints
Please attempt this question first.
From Ampere's circuital law, for a long straight wire of circular cross-section carrying a steady current, the variation of the magnetic field inside and outside the region of the wire is:
| 1. | a linearly decreasing function of distance upto the boundary of the wire and then a linearly increasing one for the outside region. |
| 2. | uniform and remains constant for both regions. |
| 3. | a linearly increasing function of distance upto the boundary of the wire and then a linearly decreasing one for the outside region. |
| 4. | a linearly increasing function of distance \(r\) upto the boundary of the wire and then decreasing one with \(1/r\) dependence for the outside region. |
Subtopic: Â Ampere Circuital Law |
 62%
From NCERT
NEET - 2022
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh
Hints
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh
- 1(current)
Q. No.
© 2024 GoodEd Technologies Pvt. Ltd.