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Q. No.A network of resistors is connected across a \(10~\text{V}\) battery with an internal resistance of \(1~\Omega\) as shown in the circuit diagram. The equivalent resistance of the circuit is:
1. \(\frac{17}{3}~\Omega\)
2. \(\frac{14}{3}~\Omega\)
3. \(\frac{12}{7}~\Omega\)
4. \(\frac{14}{7}~\Omega\)
Subtopic: Â Combination of Resistors |
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The equivalent resistance of the infinite network given below is:
1. \(2~\Omega\)
2. \((1+\sqrt2)~\Omega\)
3. \((1+\sqrt3)~\Omega\)
4. \((1+\sqrt5)~\Omega\)
1. \(2~\Omega\)
2. \((1+\sqrt2)~\Omega\)
3. \((1+\sqrt3)~\Omega\)
4. \((1+\sqrt5)~\Omega\)
Subtopic: Â Combination of Resistors |
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From NCERT
NEET - 2022
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All the resistances in the circuit shown below are \(2~\Omega.\) The equivalent resistance between \(A\) and \(C\) is:
1. \(4~\Omega\)
2. \(2~\Omega\)
3. \(\frac43~\Omega\)
4. \(\frac{10}3~\Omega\)
1. \(4~\Omega\)
2. \(2~\Omega\)
3. \(\frac43~\Omega\)
4. \(\frac{10}3~\Omega\)
Subtopic: Â Combination of Resistors |
 75%
From NCERT
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