Force on a particle F varies with time t as shown in the given graph. The displacement x vs time t graph corresponding to the force-time graph will be:
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A particle executes linear SHM between \(x=A.\) The time taken to go from \(0\) to \(A/2\) is and to go from \(A/2\) to \(A\) is , then:
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Two simple pendulums of length 1 m and 16 m are in the same phase at the mean position at any instant. If T is the time period of the smaller pendulum, then the minimum time after which they will again be in the same phase will be:
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A particle executes SHM with a time period of 4 s. The time taken by the particle to go directly from its mean position to half of its amplitude will be:
1. s
2. 1 s
3. s
4. 2 s
The graph between the velocity (v) of a particle executing S.H.M. and its displacement (x) is shown in the figure. The time period of oscillation for this SHM will be
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A simple pendulum attached to the ceiling of a stationary lift has a time period of 1 s. The distance y covered by the lift moving downward varies with time as y = 3.75 , where y is in meters and t is in seconds. If g = 10 , then the time period of the pendulum will be:
1. | 4 s | 2. | 6 s |
3. | 2 s | 4. | 12 s |
The time period of the spring-mass system depends upon:
1. | the gravity of the earth | 2. | the mass of the block |
3. | spring constant | 4. | both (2) & (3) |
Acceleration of the particle at s from the given displacement (y) versus time (t) graph will be?
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4. Zero
The displacement \( x\) of a particle varies with time \(t\) as \(x = A sin\left (\frac{2\pi t}{T} +\frac{\pi}{3} \right)\). The time taken by the particle to reach from \(x = \frac{A}{2} \) to \(x = -\frac{A}{2} \) will be:
1. | \(\frac{T}{2}\) | 2. | \(\frac{T}{3}\) |
3. | \(\frac{T}{12}\) | 4. | \(\frac{T}{6}\) |
Equation of a simple harmonic motion is given by x = asint. For which value of x, kinetic energy is equal to the potential energy?
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