A projectile is projected from the ground with the velocity v0 at an angle θ with the horizontal. What is the vertical component of the velocity of the projectile when its vertical displacement is equal to half of the maximum height attained?

1.  3v0 cosθ

2.  v02sin θ

3.  v02cosθ

4.  5v0

Subtopic:  Projectile Motion |
 70%
From NCERT
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A particle starts moving on a circular path from rest, such that its tangential acceleration varies with time as \(a_t=kt\). Distance traveled by particle on the circular path in time \(t\) is:
1. \( \frac{kt^3}{3} \)
2. \(\frac{kt^2}{6} \)
3. \(\frac{kt^3}{6} \)
4. \(\frac{k t^2}{2}\)

Subtopic:  Circular Motion |
 71%
From NCERT
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A particle is moving on a circular path of radius \(R.\) When the particle moves from point \(A\) to \(B\) (angle \( \theta\)), the ratio of the distance to that of the magnitude of the displacement will be:

         

1. θsinθ2

2. θ2sinθ2

3. θ2cosθ2

4. θcosθ2

Subtopic:  Position & Displacement |
 74%
From NCERT
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Two particles move from A to C and A to D on a circle of radius R and diameter AB. If the time taken by both particles are the same, then the ratio of magnitudes of their average velocities is:
                                
1. 2

2.  23

3.  3

4.  32

Subtopic:  Speed & Velocity |
 62%
From NCERT
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A particle moves on the curve \(x^2 = 2y\). The angle of its velocity vector with the x-axis at the point \(\left(1, \frac{1}{2}\right )\) will be:

1. \(30^\circ\) 2. \(60^\circ\)
3. \(45^\circ\) 4. \(75^\circ\)
Subtopic:  Speed & Velocity |
 61%
From NCERT
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A particle is moving along a curve. Select the correct statement.

1. If its speed is constant, then it has no acceleration.
2. If its speed is increasing, then the acceleration of the particle is along its direction of motion.
3. If its speed is decreasing, then the acceleration of the particle is opposite to its direction of motion.
4. If its speed is constant, its acceleration is perpendicular to its velocity.
Subtopic:  Acceleration |
 68%
From NCERT
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A particle starts moving from the origin in the XY plane and its velocity after time \(t\) is given by \(\overrightarrow{\mathrm{v}}=4 \hat{\mathrm{i}}+2 \mathrm{t} \hat{\mathrm{j}}\). The trajectory of the particle is correctly shown in the figure:

1. 2.
3. 4.


 

Subtopic:  Speed & Velocity |
 60%
From NCERT
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A particle is moving in the XY plane such that \(x = \left(t^2 -2t\right)\) m, and \(y = \left(2t^2-t\right)\) m, then:

1. Acceleration is zero at t = 1 sec
2. Speed is zero at t = 0 sec
3. Acceleration is always zero
4. Speed is 3 m/s at t = 1 sec
Subtopic:  Acceleration |
 70%
From NCERT
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Path of a projectile with respect to another projectile so long as both remain in the air is:

1. Circular

2. Parabolic

3. Straight

4. Hyperbolic

Subtopic:  Projectile Motion |
 67%
From NCERT
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A particle is moving along a circle of radius \(R \) with constant speed \(\mathrm{v}_0\). What is the magnitude of change in velocity when the particle goes from point \(A\) to \(B \) as shown?

                                 

1. \( 2 \mathrm{v}_0 \sin \frac{\theta}{2} \) 1. \( \mathrm{v}_0 \sin \frac{\theta}{2} \)
3. \( 2 \mathrm{v}_0 \cos \frac{\theta}{2} \) 4. \( \mathrm{v}_0 \cos \frac{\theta}{2}\)
Subtopic:  Circular Motion |
 77%
From NCERT
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