A boy throws a ball straight up the side of a building and receives it after \(4~\text s.\) On the other hand, if he throws it so that it strikes a ledge on its way up, it returns to him after \(3~\text s.\) The ledge is at a distance \(d\) below the highest point, where \(d=? \) (take acceleration due to gravity, \(g=10~\text{ms}^{-2})\)
1. \(5~\text m\)
2. \(2.5~\text m\)
3. \(1.25~\text m\)
4. \(10~\text m\)

Subtopic:  Uniformly Accelerated Motion |
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The distance travelled by a particle starting from rest and moving with an acceleration \(\frac{4}{3}\) ms-2, in the third second is:
1. \(6\) m
2. \(4\) m
3. \(\frac{10}{3}\) m
4. \(\frac{19}{3}\) m

Subtopic:  Uniformly Accelerated Motion |
 80%
From NCERT
AIPMT - 2008
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The ratio of the distances travelled by a freely falling body in the \(1\)st, \(2\)nd, \(3\)rd and \(4\)th second is:
1. \(1:1:1:1\)
2. \(1:2:3:4\)
3. \(1:4:9:16\)
4. \(1:3:5:7\)
Subtopic:  Uniformly Accelerated Motion |
 81%
From NCERT
NEET - 2022
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A stone is released from an elevator going up with an acceleration \(a.\) The acceleration of the stone after the release is:
1. \(a\) upward
2. \((g-a)\) upward
3. \((g-a)\) downward
4. \(g\) downward

Subtopic:  Uniformly Accelerated Motion |
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A particle is projected vertically upwards with a speed \(u\) and moves under the force of gravity. The distance travelled by the particle during its entire motion (until it returns) is \(d_1.\) If the force of gravity were to be switched off, and the particle travelled for the same length of time, then the distance travelled is \(d_2.\) Then, 
1. \(d_2 = d_1\)
2. \(d_2 = 2d_1\)
3. \(d_2 = 3d_1\) 
4. \(d_2 = 4 d_1\)
Subtopic:  Uniformly Accelerated Motion |
 53%
From NCERT
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