Fission of nuclei is possible because the binding energy per nucleon in them-

1.  Decreases with mass number at low mass numbers

2.  Increases with mass number at low mass numbers

3.  Decreases with mass number at high mass numbers

4.  Increases with mass number at high mass numbers

The number of beta particles emitted by a radioactive substance is twice the number of alpha particles emitted by it. The resulting daughter is an:

In the radioactive decay process, the negatively charged emitted β-particles are:

Two radioactive substances A and B have decay constants 5λ and λ respectively. At t = 0, they have the same number of nuclei. The ratio of the number of nuclei of A to those of B will be $\frac{1}{e^2}$ after a time interval:

1. $\frac{1}{4\lambda }$

2. $4\lambda$

3. $2\lambda$

4. $\frac{1}{2\lambda }$

In a radioactive material, the activity at time t₁ is R₁ and at a later time t₂, it is R₂. If the decay constant of the material is λ, then:

1. $R_1=R_2{e}^{\lambda (t_1\mathit{+}{t}_2)}$

2. $R_1=R_2{e}^{-\lambda (t_1-t_2)}$

3. $R_1=R_2(t_1-t_2)$

4. $R_1=R_2$

If M₀ is the mass of an oxygen isotope ₈O¹⁷, M_P and M_n are the masses of a proton and a neutron, respectively, the nuclear binding energy of the isotope is:

1.  ${\mathrm{M}}_{\mathrm{o}}{\mathrm{c}}^2$

2.  $\left({\mathrm{M}}_{\mathrm{o}}-17{\mathrm{M}}_{\mathrm{c}}\right) {\mathrm{c}}^2$

3.  $\left({\mathrm{M}}_{\mathrm{o}}-8{\mathrm{M}}_{\mathrm{p}}\right) {\mathrm{c}}^2$

4.  $\left(8{\mathrm{M}}_{\mathrm{p}}+9{\mathrm{M}}_{\mathrm{n}}-{\mathrm{M}}_{\mathrm{o}}\right) {\mathrm{c}}^2$

A nucleus disintegrates into two nuclear parts which have their velocities in the ratio \(2:1\). The ratio of their nuclear size will be:
1. \( 2^{1 / 3}: 1 \)
2. \( 1: 3^{1 / 2} \)
3. \( 3^{1 / 2}: 1 \)
4. \( 1: 2^{1 / 3}\)