Q. No.The value of Planck's constant is 6.63 × 10–34 Js. The speed of light is 3 × 1017 nm s–1. Which value is closest to the wavelength in nanometers of a quantum of light with a frequency of 6 × 1015 s–1?
1. 25
2. 50
3. 75
4. 10
n = 3, l = 1 and m = –1.
2. 4
3. 2
4. 10
Based on equation E = –2.178 × 10–18J, certain conclusions are written. Which of them is not correct?
| 1. | Larger the value of n, the larger the orbit radius. |
| 2. | Equation can be used to calculate the change in energy when the electron changes orbit. |
| 3. | For n = 1, the electron has a more negative energy than it does for n = 6 which means that the electron is more loosely bound in the smallest allowed orbit. |
| 4. | The negative sign in the equation simply means that the energy of the electron bound to the nucleus is lower than what it would be if the electrons were at an infinite distance from the nucleus. |
Consider the following sets of quantum numbers:
| n | I | m | s | |
| (i) | 3 | 0 | 0 | +1/2 |
| (ii) | 2 | 2 | 1 | +1/2 |
| (iii) | 4 | 3 | -2 | -1/2 |
| (iv) | 1 | 0 | -1 | -1/2 |
| (v) | 3 | 2 | 3 | +1/2 |
Which of the following sets of quantum numbers is not possible?
1. ii, iii, and iv
2. i, ii, iii, and iv
3. ii, iv and v
4. i and iii
4d, 5p, 5f and 6p orbitals are arranged in the order of decreasing energy. The correct option is:
| 1. | 5f > 6p > 4d > 5p | 2. | 5f > 6p > 5p > 4d |
| 3. | 6p > 5f > 5p > 4d | 4. | 6p > 5f > 4d > 5p |
Which of the following series of transitions in the spectrum of hydrogen atoms falls in the visible region?
1. Brackett series
2. Lyman series
3. Balmer series
4. Paschen series
Calculate the energy corresponding to light of wavelength 45 nm:
(Planck's constant h = 6.63 × 10–34 Js & speed of light c = 3 × 108 ms–1)
1. 6.67 x 1015 J
2. 6.67 x 1011 J
3. 4.42 x 10-15 J
4. 4.42 x 10-18 J
What is the maximum number of orbitals that can be identified with the following quantum numbers?
n = 3, l = 1, m = 0
| 1. | 1 | 2. | 2 |
| 3. | 3 | 4. | 4 |
The number of d -electrons in Fe2+ (atomic number Z = 26) is different from the number of:
1. s-electrons in Mg (Z = 12)
2. p-electrons in Cl (Z = 17)
3. d-electrons in Fe (Z = 26)
4. p-electrons in Ne (Z = 10)
Which is the correct order of increasing energy of the listed orbitals in the atom of titanium?
1. 3s 4s 3p 3d
2. 4s 3s 3p 3d
3. 3s 3p 3d 4s
4. 3s 3p 4s 3d
© 2025 GoodEd Technologies Pvt. Ltd.