The slopes of isothermal and adiabatic curves are related as:
1. Isothermal curve slope = adiabatic curve slope
2. Isothermal curve slope = \(\gamma \times\) adiabatic curve slope
3. Adiabatic curve slope = \(\gamma \times\) isothermal curve slope
4. Adiabatic curve slope = \(\frac{1}{2}\times\) isothermal curve slope

Subtopic:  Types of Processes |
 75%
Level 2: 60%+
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During the adiabatic expansion of 2 moles of a gas, the internal energy of the gas is found to decrease by 2 joules, the work done during the process by the gas will be equal to -

(1) 1 J

(2) –1 J

(3) 2 J

(4) – 2 J

Subtopic:  First Law of Thermodynamics |
 64%
Level 2: 60%+
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If γ denotes the ratio of two specific heats of a gas, the ratio of slopes of adiabatic and isothermal PV curves at their point of intersection is 

(1) 1γ

(2) γ

(3) γ-1

(4) γ+1

Subtopic:  Types of Processes |
 80%
Level 1: 80%+
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Air in a cylinder is suddenly compressed by a piston, which is then maintained at the same position. With the passage of time 

1. The pressure decreases
2. The pressure increases
3. The pressure remains the same
4. The pressure may increase or decrease depending upon the nature of the gas
Subtopic:  Types of Processes |
Level 3: 35%-60%
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The adiabatic Bulk modulus of a perfect gas at pressure P is given by 

(1) P

(2) 2P

(3) P/2

(4) γ P

Subtopic:  Types of Processes |
 78%
Level 2: 60%+
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An adiabatic process occurs at constant 

(1) Temperature

(2) Pressure

(3) Heat

(4) Temperature and pressure

Subtopic:  Types of Processes |
 84%
Level 1: 80%+
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For adiabatic processes γ=CpCv 

(1) PγV = constant

(2) TγV = constant

(3) TVγ1 = constant

(4) TVγ = constant

Subtopic:  Types of Processes |
 90%
Level 1: 80%+
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An ideal gas is expanded adiabatically at an initial temperature of \(300~\text{K}\) so that its volume is doubled. The final temperature of the hydrogen gas is: \((\gamma = 1.40)~\left[2^{0.4}= 1.3\right]\)
1. \(230.76~\text{K}\)
2. \(500.30~\text{K}\)
3. \(454.76~\text{K}\)
4. \(-47~^{\circ}\text{C}\)

Subtopic:  Types of Processes |
 76%
Level 2: 60%+
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In an adiabatic expansion of a gas, if the initial and final temperatures are \(T_1\) and \(T_2\), respectively, then the change in internal energy of the gas is:
1. \(\frac{nR}{\gamma-1}(T_2-T_1)\)
2. \(\frac{nR}{\gamma-1}(T_1-T_2)\)
3. \(nR ~(T_1-T_2)\)
4. Zero

Subtopic:  First Law of Thermodynamics |
 69%
Level 2: 60%+
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Helium at 27°C has a volume of 8 litres. It is suddenly compressed to a volume of 1 litre. The temperature of the gas will be [γ = 5/3] 

(1) 108°C

(2) 9327°C

(3) 1200°C

(4) 927°C

Subtopic:  Types of Processes |
 66%
Level 2: 60%+
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