The amplitude of a particle executing SHM is 4 cm. At the mean position the speed of the particle is 16 cm/sec. The distance of the particle from the mean position at which the speed of the particle becomes 83cm/sec will be

1.   23cm             

2.  3cm

3.  1 cm                   

4.  2 cm

Subtopic:  Simple Harmonic Motion |
 70%
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The maximum velocity of a simple harmonic motion represented by y=3sin100t+π6 is given by

1. 300       

2.  3π6

3. 100         

4.  π6

Subtopic:  Simple Harmonic Motion |
 93%
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The instantaneous displacement of a simple pendulum oscillator is given by x=Acosωt+π4 . Its speed will be maximum at time

1. π4ω      

2. π2ω

3. πω                

4. 2πω

Subtopic:  Simple Harmonic Motion |
 61%
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A particle moving along the x-axis executes simple harmonic motion, then the force acting on it is given by

1.  – A Kx           

2.  A cos (Kx)

3.  A exp (– Kx

4.  A Kx

Subtopic:  Simple Harmonic Motion |
 84%
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For a particle executing simple harmonic motion, the kinetic energy K is given by k=kοcos2ωt. The maximum value of potential energy is

1. Kο                     

2. Zero

3. Kο2                 

4. Not obtainable

Subtopic:  Energy of SHM |
 66%
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A particle is executing simple harmonic motion with frequency \(f\). The frequency at which its kinetic energy changes into potential energy, will be:
1. \(\frac{f}{2}\)
2. \(f\)
3. \(2f\)
4. \(4f\)
Subtopic:  Energy of SHM |
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There is a body having mass m and performing S.H.M. with amplitude a. There is a restoring force ,F=-Kx where x is the displacement. The total energy of body depends upon -

1.  K, x         

2.  K, a

3.  K, a, x    

4.  K, a, v

Subtopic:  Energy of SHM |
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A body executes simple harmonic motion. The potential energy (P.E.), the kinetic energy (K.E.) and total energy (T.E.) are measured as a function of displacement x. Which of the following statements is true ?

1. P.E. is maximum when x = 0

2. K.E. is maximum when x = 0

3. T.E. is zero when x = 0

4. K.E. is maximum when x is maximum

Subtopic:  Energy of SHM |
 87%
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A simple pendulum is suspended from the roof of a trolley which moves in a horizontal direction with an acceleration a, then the time period is given by T=2πlg',  where g'   is equal to

1. g                                                       

2. g-a

3. g+a

4. g2+a2

Subtopic:  Angular SHM |
 87%
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The kinetic energy of a particle executing S.H.M. is 16 J when it is in its mean position. If the amplitude of oscillations is 25 cm and the mass of the particle is 5.12 kg, the time period of its oscillation is -

(1) π5sec       

(2) 2πsec

(3) 20πsec   

(4) 5πsec

Subtopic:  Energy of SHM |
 66%
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