• Subject:

...

• Topic:

...

The two ends of a rod of length L and a uniform cross-sectional area A are kept at two temperatures The rate f heat transfer, $\frac{dQ}{dt},$ through the rod in a steady state is given by

(a) $\frac{dQ}{dt}=\frac{KL\left({T}_{1}-{T}_{2}\right)}{A}$                       (b) $\frac{dQ}{dt}=\frac{KL\left({T}_{1}-{T}_{2}\right)}{LA}$

(c) $\frac{dQ}{dt}=KLA\left({T}_{1}-{T}_{2}\right)$                      (d) $\frac{dQ}{dt}=\frac{KL\left({T}_{1}-{T}_{2}\right)}{L}$

NEET