NEET Questions Solved

NEET - 2010

The energy of a hydrogen atom in the ground state is -13.6 eV. The energy of a He+ ion in the first excited state will be 

(a) -13.6 eV

(b) -27.2 eV

(c) -54.4 eV

(d) -6.8 eV

Energy E of an atom with principal quantum number n is given by E=-13.6n2Z2 for first excited state n=2 and for He+ Z=2

           E=-13.6×2222

               =-13.6 eV

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