# NEET Questions Solved

NEET - 2014

If the kinetic energy of the particle is instead to 16 times its previous value, the percentage change in the de-Broglie wavelength of the particle is

(a) 25

(b) 75

(c) 60

(d) 50

For de-Broglie wavelength

$\lambda$1=h/p=h/√2mK ...(i)

$\lambda$2=h/√2m16K=h/4√2mK=$\lambda$1/4 ...(ii)

$\lambda$2=25% of $\lambda$1

There is 75% change in the wavelength

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