# NEET Practice Questions

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NEET, 2016

Electrons of mass m with de-Brogile wavelength $\lambda$ fall on the target in an X-ray tube. The cut off wavelength $\left({\lambda }_{0}\right)$ of the emitted X-ray is

(a) ${\lambda }_{0}=\frac{2mc{\lambda }^{2}}{h}$          (b) ${\lambda }_{0}=\frac{2h}{mc}$

(c) ${\lambda }_{0}=\frac{2{m}^{2}{c}^{2}{\lambda }^{3}}{{h}^{2}}$       (d) ${\lambda }_{0}=\lambda$